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3 years ago

PLEASE ANSWER

Chemistry

1 answer:

stepladder [879]3 years ago

8 0

Answer:

C. Light slows down as it goes through more dense materials.

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2FePO, + 3Na S0,

trapecia [35]

26.5 g of Fe₂(SO₄)₃

Explanation:

We have the following chemical reaction:

2 FePO₄ + 3 Na₂SO₄ → Fe₂(SO₄)₃ + 2 Na₃PO₄

number of moles = mass / molecular wight

number of moles of FePO₄ = 20 / 151 = 0.1325 moles

Taking in account the chemical reaction we devise the following reasoning:

if 2 moles of FePO₄ produces 1 mole of Fe₂(SO₄)₃

then 0.1325 moles of FePO₄ produces X moles of Fe₂(SO₄)₃

X = (0.1325 × 1) / 2 = 0.06625 moles of Fe₂(SO₄)₃

mass = number of moles × molecular wight

mass of Fe₂(SO₄)₃ = 0.06625 × 400 = 26.5 g

Learn more about:

number of moles

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3 0

4 years ago

how many molecule of carbon dioxide are needed to react with excess iron oxide to produce 11.6 g of iron

lesya692 [45]

Answer:

0.16 moles of Carbon

Explanation:

The balanced reaction equation:

$2Fe_{2}O_{3}$ + $3C$ → $4Fe$ + $3CO_{2}$ ↑

The mole ratio of Carbon to Iron is 3 : 4 (since Fe2O3 is in excess)

i.e 3 moles of C produces 4 moles of Fe.

If 1 mole of Fe - 55.8g of Fe

? moles - 11.6g of Fe

= $\frac{11.6}{55.8}$ = 0.208 moles

But 3 moles of C - 4 moles of Fe

? moles of C - 0.208 moles of Fe

= $\frac{3 *0.208}{4}$ = 0.16 moles of carbon.

I hope this explanation was clear and useful.

5 0

4 years ago

Helpppp helpppp plsssss

Sedbober [7]

$\Large \text{1)}$

$\textbf{Use the formula and substitute the values}$

$\displaystyle 0.3\ mol/L = \frac{n \ mol}{10 \times 10^{-3}\ L}$

$\textbf{Solve for the number of moles}$

$n = 0.003\ mol$

$\textbf{Calculate final volume }$

$40+10=50\ mL$

$\textbf{Number of moles remains same. Solve for concentration}$

$\displaystyle C=\frac{0.003\ mol}{50 \times 10^{-3}\ L} =0.06\ mol/L$

$\Large \text{2)}$

$\displaystyle DF=\frac{V_f}{V_i}$

$\displaystyle DF=\frac{50}{10}=5$

3 0

3 years ago

What gas is stored in gas cylinders? <br>

Igoryamba

Answer: Oxygen, Nitrogen, And Nitrous Oxide

Explanation:

Oxygen, Nitrogen, And Nitrous Oxide Are Just Some Of The Gasses Stored In Gas Cylinders,

4 0

3 years ago

In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide Al2O3 dissolved in molten c

gtnhenbr [62]

Answer:

1.13 × 10⁶ g

Explanation:

Let's consider the reduction of aluminum (III) from Al₂O₃ to pure aluminum.

Al³⁺ + 3 e⁻ → Al

We can establish the following relations:

1 Ampere = 1 Coulomb / second
The charge of 1 mole of electrons is 96,468 c (Faraday's constant)
1 mole of Al is produced when 3 moles of electrons circulate
The molar mass of Al is 26.98 g/mol.

The mass of aluminum produced under these conditions is:

$90.0 s \times \frac{1s}{620c} \times \frac{96,468c}{1mole^{-} } \times \frac{3mole^{-}}{1molAl} \times \frac{26.98gAl}{1molAl} =1.13 \times 10^{6} g Al$

6 0

4 years ago