Answer:
1 km * 1000 m / km * 100 cm / m = 10^5 cm / km
V = 4 / 3 pi R^3
V = 4 / 3 * pi * (7.01 * 10^5 * 10^5)^3 = 4 / 3 pi * 344 * (10^10)^3
V = 1.443^10^3 * 10^30 = 1.44 10^33cm^3
The correct answer is Shale
I suggest you to go with C !! it is absolutely wrong sentence !!
increasing the gas particles will increase the collision between them so !!
your answer is C !!
The balanced equation for the neutralisation reaction is as follows
2NaOH + H₂SO₄ ---> Na₂SO₄ + 2H₂O
stoichiometry of NaOH to H₂SO₄ is 2:1
the number of moles of NaOH reacted - 0.126 mol/L x 0.0173 L = 0.00218 mol
if 2 mol of NaOH reacts with 1 mol of H₂SO₄
then 0.00218 mol of NaOH reacts with - 0.00218 / 2 = 0.00109 mol of H₂SO₄
molarity is the number of moles of solute in 1 L solution
therefore if 25 mL contains - 0.00109 mol
then 1000 mL contains - 0.00109 mol / 25 mL x 1000 mL = 0.0436 mol/L
therefore molarity of H₂SO₄ is 0.0436 M
Answer:
Explanation:
use the equation
moles = mass/mr
=19.9/79.5
=0.250moles of CuO
then do the same for
H = 2.02/1
=2.02
so CuO is the limiting reagent because there is less amount of it.
Hope this helps :)
