The grams of Mg(OH)2 produced is calculated as below
calculate the moles of HCl produced =molarity xvolume/1000
= 0.3 x 435/1000= 0.1305 moles
write the equation for reaction
Mg(OH)2 +2HCl = MgCl2 + 2H2O
by use of mole ratio between HCl :MgCl2 which is 2 :1 the moles of HCl = 0.1305 x1/2 =0.0653 moles of MgCl2
mass of MgCl2 = moles x molar mass
= 0.0653mol x95 g/mol = 6.204 grams of MgCl2
Answer:
See explanation
Explanation:
When an a heavy object and a light object are thrown down from the same height, the two objects are expected to hit the ground at the same time since the two objects are both accelerated to the same extent (approximately 10m/s^2) under gravity.
However, due to air resistance, the heavier object reaches the ground first before the lighter object.
Hence, when we drop a feather and a stone at the same time from a height the stone will hit the ground faster than the feather.
The molecular geometry of a compound helps to determine polarity b/c, it indicates the number of lone pairs on a central atom thus giving it specified angles and polarity (only if there are lone pairs b/c if there are no lone pairs on the central atom, then it is nonpolar.
Answer:-
190.23 gram mol-1
Explanation:-
Molar mass is the mass of 1 mole of that substance. It's unit is gram / mol or gram mol-1.
For an element it is equal to it's atomic weight.
The atomic weight of Osmium is 190.23
Hence the molar mass of Osmium is 190.23 gram / mol
A gravity well is the pull of gravity that a large body in space exerts. The larger the body (the more mass) the more of a gravity well it has. The Sun has a large (or deep) gravity well. Asteroids and small moons have much shallower gravity wells. Anything on a planet or moon is considered to be at the bottom of the gravity well. Entering space from the surface of a planet or moon means climbing out of the gravity well, something that often takes a huge amount of energy. The larger a planet or moon's gravity well is, the more energy it takes to achieve escape velocity and blast a ship off of it.
