Answer:
11.725%
Step-by-step explanation:
Given that :
True value = 0.904 seconds
Measured time = 1.010 seconds
Experimental error :
(|measured value - True value | / true value) * 100%
(|1.010 - 0.904| ÷ 0.904) * 100%
= 0.106 / 0.904 * 100%
= 0.1172566 * 100%
= 11.725%
Since, population of species A is represented by : 
Let us find the population of species A, at the end of week 1:
i.e., x = 1
i.e., 
i.e., 
i.e., 
Also, since population of species B is represented by : 
Let us find the population of species B, at the end of week 1:
i.e., x = 1
i.e., 
i.e., 
i.e., 
Thus, at the end of 1 week, species A and species B will have the same population.
Hence, option D is correct.
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