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eduard
3 years ago
9

Find the solution of. 5b - 13= 22 if the replacement set is {5,6,7,8,9}

Mathematics
2 answers:
grandymaker [24]3 years ago
8 0
5b-13=22
+13. +13
----------------
5b = 35
---- ----
5. 5
b= 7
ira [324]3 years ago
7 0
The answer is u 7 bro

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If you roll a number cube 12 times, about how many times would you expect to roll a 5 or 6
Marrrta [24]
You have a 1/3 chance each time you role So 1/3 x 12 = 4 times that you would role a 5 or a 6
6 0
3 years ago
(28⋅ 5−5⋅ 190)−2⋅⋅ 228 in simplified form I NEED HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
melisa1 [442]

Answer:

-1266

Step-by-step explanation:

(28 \times 5 - 5 \times 190) - 2 \times 228 \\ (140 - 950) - 456 \\ ( - 810) - 456 \\  - 810 - 456

=  - 1266

6 0
3 years ago
74.823 WHAT IS THE PLACE VALUE OF THE 3?
Ipatiy [6.2K]
One thousandths. make sure you add the ths because it is a decimal
4 0
3 years ago
Read 2 more answers
Write the equation of the circle with center (5, 1) and radius r = 10
kherson [118]
The standard equation for the circle is:

(x-h)^2+(y-k)^2=r^2, where (h,k) is the center of the circle and r is the radius.

We are given that the center is (5,1) and r=10 so

(x-5)^2+(y-1)^2=100
4 0
3 years ago
Someone help me with this I will make you brain
hram777 [196]

Step-by-step explanation:

let's look at the full numbers under the square roots when bringing the external factors back in :

sqrt(9×9×2) - sqrt(3×3×7) + sqrt(8) - sqrt(28)

and let's present these numbers as the product of their basic prime factors

sqrt(3×3×3×3×2) - sqrt(3×3×7) + sqrt(2×2×2) - sqrt(2×2×7)

now we see that we have 2 pairs of square roots : 1 pair ends with a factor of 2, and one pair with a factor of 7.

let's combine these

sqrt (3×3×3×3×2) + sqrt(2×2×2) - sqrt(3×3×7) - sqrt (2×2×7)

and now we move the factors of 2 and 7 back out in front (of course, we need to apply the square root on these factors) :

9×sqrt(2) + 2×sqrt(2) - 3×sqrt(7) - 2×sqrt(7) =

= (9+2)×sqrt(2) - (3+2)×sqrt(7) = 11×sqrt(2) - 5×sqrt(7)

and that is the first answer option.

5 0
3 years ago
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