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3 years ago

Evaluate the function f(x)=x+4 when x=3.

Mathematics

1 answer:

ella [17]3 years ago

4 0

Since x=3 that means all of the x's would be 3's

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Leo, Kush and Mai share some money in the ratio 3:5:8

Marta_Voda [28]

Answer:

The total amount of money that they shared is $\£6,000$

Step-by-step explanation:

Let

x-----> amount of money Leo shares

y-----> amount of money Kush shares

z-----> amount of money Mai shares

we know that

$\frac{x}{y} =\frac{3}{5}$

$x=\frac{3}{5}y$ -----> equation A

$\frac{y}{z} =\frac{5}{8}$

$z=\frac{8}{5}y$ -----> equation B

$\frac{x}{z} =\frac{3}{8}$

$z=\frac{8}{3}x$ -----> equation C

$y=x+750$ ------> equation D

substitute equation A in equation D and solve for y

$y=\frac{3}{5}y+750$

$y-\frac{3}{5}y=750$

$\frac{2}{5}y=750$

$y=750*5/2=\£1,875$

Find the value of x (equation A)

$x=\frac{3}{5}(1,875)=\£1,125$

Find the value of z (equation C)

$z=\frac{8}{3}(1,125)=\£3,000$

therefore

The total amount of money is equal to

$x+y+z=\£1,125+\£1,875+\£3,000=\£6,000$

5 0

3 years ago

You borrow 125,000 for 25 years at an APR of 6.5%. What will be your monthly payment?

Morgarella [4.7K]

$\bf \qquad \qquad \textit{Amortized Loan Value}
\\\\
pymt=P\left[ \cfrac{\frac{r}{n}}{1-\left( 1+ \frac{r}{n}\right)^{-nt}} \right]
\\\\\\\\
\qquad 
\begin{cases}
P=
\begin{array}{llll}
\textit{original amount}\\
\end{array}\to &
\begin{array}{llll}
125000
\end{array}\\
pymt=\textit{periodic payments}\\
r=rate\to 6.5\%\to \frac{6.5}{100}\to &0.065\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{APR, meaning once}
\end{array}\to &1\\

t=years\to &25
\end{cases}$

8 0

2 years ago

Suppose one bottle of paint can cover 20 tiles. you have 348 tiles. how many bottles of paint do you need to buy to cover all 34

kap26 [50]

Well first u need 2 divide 20/348 Because u need to fiend HOW MANY U NEED so that means you need to divide And that's how many Tiles

4 0

3 years ago

9<br> Write as a percentage.<br> 10

Ludmilka [50]

Answer:

Step-by-step explanation:

I really dont know but if I did I would say I'm a 6 grader

8 0

3 years ago

Help me pleeeeeeeeeaze

kobusy [5.1K]

$a(x+3) < 5x+15-x\\\\ax+3a < 5x+15-x\\\\ax+3a < 4x+15\ \ \ |-3a\\\\ax < 4x+15-3a\ \ \ \ |-4x\\\\ax-4x < 15-3a\\\\(a-4)x < 15-3a\\\\\text{The solution is all real numbers if}\ a-4=0\ \ \ |+4\\\\\boxed{a=4}\\\\\text{Check:}\\\\4(x+3) < 5x+15-x\\4x+12 < 4x+15\ \ \ \ |-4x\\12 < 15\ TRUE\to x\in\mathbb{R}$

5 0

3 years ago