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Pepsi [2]
2 years ago
11

Three collinear forces,F1=45N west,F2=63N east and an unknown force F3 are applied to an object.The resultant force of the three

forces is 12N west.
Show by means of a tail to head method of vector addition how the magnitude of F3 could be found?​
Physics
1 answer:
Greeley [361]2 years ago
6 0

Take east to be the positive direction. Then the resultant force from adding <em>F</em>₁ and <em>F</em>₂ is

<em>F</em>₁ + <em>F</em>₂ = (-45 N) + 63 N = 18 N

which is positive, so it's directed east.

To this we add a third force <em>F</em>₃ such that the resultant is 12 N pointing west, making it negative, so that

18 N + <em>F</em>₃ = -12 N

<em>F</em>₃ = -30 N

So <em>F</em>₃ has a magnitude of 30 N and points west.

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In a candy factory, the nutty chocolate bars contain 20.0 % pecans by mass. If 4.0 kg of pecans were used for candy last Tuesday
ladessa [460]

Answer:

44.09 pounds

Explanation:

We got that 20 % of the mass of a nutty chocolate bar its pecans, if 4.0 kg of pecans were used, we need to find the X in the equation

0.2 * X = 4.0 \ kg

where X its the total mass of nutty chocolate bars produced. So, we can just divide by 0.2 on both sides, and we find:

X = 4.0 kg / 0.2

X = 20.0 \ kg

Of course, we need the total mass produced in pounds, and not in kilograms.  Looking at an conversion table, we can find that 1 kg its 2.20462 pounds, multiplying the value for total mass produced by the conversion factor we get:

X = 20.0 \ kg * 2.20462 \ \frac{pounds}{kg}

X = 44.0924 \ pounds

Now, we just need to round off to two significant figures. This is:

X = 44.09 \ pounds,

the total mass of nutty chocolate bars  made last Tuesday to two significant figures.

5 0
3 years ago
Which calculates the intensity of an electric field at a point where a 0.50 C charge experiences a force of 20. N?
tester [92]

Answer: 40\ N/C

Explanation:

Given

Magnitude of charge is q=0.5\ C

Force experienced is F=20\ N

Electric field intensity is the electrostatic force per unit charge

\therefore E=\dfrac{F}{q}\\\\\Rightarrow E=\dfrac{20}{0.50}\\\\\Rightarrow E=40\ N/C

Thus, the electric field intensity is 40\ N/C

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3 years ago
a runner increases her speed from 3.1 m/s to 3.5 m/s during the last 15 seconds of her run, what was her acceleration during her
Rama09 [41]
Acceleration = velocity/time
A= 3.5m/s/15s
A= 0.23m/s^2
5 0
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Answer:

D

Explanation:

<em>The correct answer would be in the axle of the wheels while you ride your bicycle.</em>

Options A, B, and C requires that the forces of friction is increased in order to have more control.

However, option D requires that there is a minimal frictional force in the axle of the wheels of a bicycle while riding so that a little effort would be required to keep the bicycle moving.

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4 0
2 years ago
a pelican flying along a horizontal path drops a fish from a height of 5.4m. the fish travels 8.0m horizontally before it hits t
oksian1 [2.3K]

Answer:

7.0 m/s

Explanation:

6 0
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