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Arada [10]
3 years ago
9

A simple pendulum is used to determine the acceleration due to gravity at the surface of a planet. The pendulum has a length of

2 m and its period is measured to be 2 s. The value of g obtained in this investigation is most nearly __________.A. 1 m/s²B. 2 m/s²C. 5 m/s²D. 10 m/s²E. 20 m/s²
Physics
1 answer:
SVEN [57.7K]3 years ago
8 0

Answer:

Acceleration due to gravity is 20 m/sec^2

So option (E) will be correct answer

Explanation:

We have given length of the pendulum l = 2 m

Time period of the pendulum T = 2 sec

We have to find acceleration due to gravity g

We know that time period of pendulum is given by

T=2\pi \sqrt{\frac{l}{g}}

2=2\times 3.14 \sqrt{\frac{2}{g}}

0.3184= \sqrt{\frac{2}{g}}

Squaring both side

0.1014= {\frac{2}{g}}

g=19.71=20m/sec^2

So acceleration due to gravity is 20 m/sec^2

So option (E) will be correct answer.

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Explanation :

It is given that,

Diameter of the coil, d = 20 cm = 0.2 m

Radius of the coil, r = 0.1 m

Number of turns, N = 3000

Induced EMF, \epsilon=1.5\ V

Magnitude of Earth's field, B=10^{-4}\ T

We need to find the angular frequency with which it is rotated. The induced emf due to rotation is given by :

\epsilon=NBA\omega

\omega=\dfrac{\epsilon}{NBA}

\omega=\dfrac{1.5}{3000\times 10^{-4}\times \pi (0.1)^2}

\omega=159.15\ rad/s

So, the angular frequency with which the loop is rotated is 159.15 rad/s. Hence, this is the required solution.

3 0
3 years ago
A 10,000 N net force is accelerating a car at a rate of 5.5m/s^2. What is the cars mass
ycow [4]

Answer:

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Explanation:

6 0
3 years ago
Select the correct answer.
spin [16.1K]

Answer:

There isnt enough in your question to answer the question bro, like we need a picture or something bro.

Explanation:

7 0
3 years ago
A 500 N weight sits on the small piston of a hydraulic machine. The small piston has area 2.0 cm2. If the large piston has area
Ghella [55]

Answer:

d. 10000N

Explanation:

When a force (F_1) is exerted on the smaller area piston (A_1), the pressure that originates therein is transmitted to the larger area piston(A_2). According to Pascal's principle the pressure on the smallest piston (P_1=\frac{F_1}{A_1}) will be equal to the pressure on the largest piston (P_2=\frac{F_2}{A_2}):

\frac{F_1}{A_1}=\frac{F_2}{A_2}\\F_2=F_1\frac{A_2}{A_1}\\F_2=500N\frac{40cm}{2cm}\\F_2=10000N

7 0
3 years ago
Select the correct answer.
r-ruslan [8.4K]

Answer:

That would be B. Hope this helps!

Explanation:

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3 0
3 years ago
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