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2 years ago

The magnitude of a uniform electric field between two plates is about 1.7 × 106N/C. If the distance

Physics

1 answer:

ASHA 777 [7]2 years ago

4 0

Answer:

V = E*d

D = 1.5 cm * [1 m / 100 cm] = 0.015m

V = 2.9^10^6 N/C * 0.015 m

V = 1.93 * 10^9 V

The units don't agree in any simple way, but the formula is correct, and it does work.

Explanation:

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Who created earthquake proof buildings?

klemol [59]

Answer:

Japanese created earthquake proof buildings

Explanation:

Countries like Japan where earthquakes are regular. So these important factors are downgraded to nice -to-haves behind the need of Japan structural stability. The Pacific ring of Fire and all its seismic activities are contributed to Japans strict building codes for skyscrapers and Towers. Building codes means, earthquakes proof structures are intended to withstand the earthquake.The prime example of an earthquake-ready country is Japan with its dedication to structural stability.

5 great examples are

1. Mori Tower

2. Tokyo Skytree

3. Ark Hills Sengokuyama

4.fa-bo

5. Television House

8 0

3 years ago

A low orbit satellite at 100 km altitude had a camera that resolved a car location to within 0.3 meter. Find the minimum diamete

NeX [460]

Answer:

Minimum diameter of the camera lens is 22.4 cm

The focal length of the camera's lens is 300cm

Explanation:

y = Resolve distance = 0.3 m

h = Height of satellite = 100 km

λ = Wavelength = 550 nm

Angular resolution

$tan\theta\approx \theta =\frac{y}{h}\\\Rightarrow \theta=\frac{0.3}{100\times 10^3}=3\times 10^{-6}$

From Rayleigh criteria

$sin\theta=1.22\frac{\lambda}{D}\\\Rightarrow D=1.22\frac{\lambda}{sin\theta}\\\Rightarrow D=1.22\frac{550\times 10^{-9}}{sin3\times 10^{-6}}=0.2236\ m=22.4\ cm$

Minimum diameter of the camera lens is 22.4 cm

Relation between resolvable feature, focal length and angular resolution

$d=f\Delta \theta\\\Rightarrow f=\frac{d}{\Delta \theta}\\\Rightarrow f=\frac{9\times 10^{-6}}{3\times 10^{-6}}=3\ m=300\ cm$

The focal length of the camera's lens is 300cm

3 0

3 years ago

What is 1113.28 in a sig fig?

Afina-wow [57]

Answer:

6 significant figure

Explanation:

The digits 111328 all are 6 figures with no figure being zero, neither zero after the other digits. In this case, all the numbers are significant and since they are only six numbers, then this is a six significant figure. In case we add another zero after digit 8, the zero is not significant but if added either infront of 8 or 2, the zero becomes significant.

4 0

3 years ago

Suppose that a comet has a very eccentric orbit that brings it quite close to the Sun at closest approach (perihelion) and beyon

Nutka1998 [239]

Answer:

16.63min

Explanation:

The question is about the period of the comet in its orbit.

To find the period you can use one of the Kepler's law:

$T^2=\frac{4\pi}{GM}r^3$

T: period

G: Cavendish constant = 6.67*10^-11 Nm^2 kg^2

r: average distance = 1UA = 1.5*10^11m

M: mass of the sun = 1.99*10^30 kg

By replacing you obtain:

$T=\sqrt{\frac{4\pi}{GM}r^3}=\sqrt{\frac{4\pi^2}{(6.67*10^{-11}Nm^2/kg^2)(1.99*10^{30}kg)}(1.496*10^8m)^3}\\\\T=997.9s\approx16.63min$

the comet takes around 16.63min

8 0

3 years ago

A wave of wavelength 0.3 m travels 900 m in 3.0 s. Calculate its frequency.

Crank

Answer: 1000 Hz

Explanation:

You can calculate frequency by dividing velocity by wavelength

Frequency = velocity/wavelength

Find velocity first.

900 m/3 s = 300 m/s

Plug values in to find frequency.

F = (300 m/s)/0.3 m

F = 1000 Hz

8 0

3 years ago