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Vesna [10]
2 years ago
6

The magnitude of a uniform electric field between two plates is about 1.7 × 106N/C. If the distance

Physics
1 answer:
ASHA 777 [7]2 years ago
4 0

Answer:

V = E*d

D = 1.5 cm * [1 m / 100 cm] = 0.015m

V = 2.9^10^6 N/C * 0.015 m

V = 1.93 * 10^9 V

The units don't agree in any simple way, but the formula is correct, and it does work.

Explanation:

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C. Beats

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Starting from rest, a disk rotates about its central axis with constant angular acceleration. In 5.00 s, it rotates 14.8 rad. Du
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Answer:

Explanation:

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What is the maximum value of the magnetic field at a<br> distance2.5m from a 100-W light bulb?
MA_775_DIABLO [31]

To solve this problem we will apply the concepts related to the intensity included as the power transferred per unit area, where the area is the perpendicular plane in the direction of energy propagation.

Since the propagation occurs in an area of spherical figure we will have to

I = \frac{P}{A}

I = \frac{P}{4\pi r^2}

Replacing with the given power of the Bulb of 100W and the radius of 2.5m we have that

I = \frac{100}{4\pi (2.5)^2}

I = 1.2738W/m^2

The relation between intensity I and E_{max}

I = \frac{E_max^2}{2\mu_0 c}

Here,

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Rearranging for the Maximum Energy and substituting we have then,

E_{max}^2 = 2I\mu_0 c

E_{max}=\sqrt{2I\mu_0 c }

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B_{max} = \frac{E_{max}}{c}

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3 0
3 years ago
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