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Vesna [10]
3 years ago
6

The magnitude of a uniform electric field between two plates is about 1.7 × 106N/C. If the distance

Physics
1 answer:
ASHA 777 [7]3 years ago
4 0

Answer:

V = E*d

D = 1.5 cm * [1 m / 100 cm] = 0.015m

V = 2.9^10^6 N/C * 0.015 m

V = 1.93 * 10^9 V

The units don't agree in any simple way, but the formula is correct, and it does work.

Explanation:

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Wave A has an amplitude of 2 and wave B has an amplitude of 2 as shown below. What will happen when the crest of wave A meets th
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A photon with an energy E = 2.12 GeV creates a proton-antiproton pair in which the proton has a kinetic energy of 96.0 MeV. What
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Answer:

The kinetic energy of the anti proton is 147.4 MeV.

Explanation:

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E_{photon}=m_{p}c^2+m_{np}c^2+K.E_{p}+K.E_{np}

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Put the value into the formula

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3 years ago
Identify each wave interaction based on how it changes direction.___
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