What does the green material in a plant called?

For a molecule to be considered inorganic it must not contain ?

horsena [70]

Answer:

It must not contain protein.

8 0

4 years ago

"Alkenes" ________.are reasonably soluble in water are relatively polar compounds have lower boiling points than alcohols of sim

aleksandr82 [10.1K]

Answer:

The answer to your question is: the third option is correct.

Explanation:

"Alkenes" ________.

are reasonably soluble in water This option is incorrect, alkenes are insoluble in water.

are relatively polar compounds This option is wrong, alkenes are not polar molecules.

have lower boiling points than alcohols of similar molecular weight This option is true, alkenes have a lower boiling point than alcohols.

both have lower boiling points than alcohols of similar molecular weight and are relatively polar compounds. This option is incorrect because is combining true with false facts.

8 0

3 years ago

What is the energy required to remove the electron from a hydrogen atom in the n = 11 state?

zaharov [31]

Based on the data given, the energy required to remove an electron from a hydrogen atom in the n = 11 state is -0.112 eV

<h3>What is ionization energy?</h3>

Ionization energy is the energy requiredto remove an electron from a neutral atom or a cation in its gaseous state.

To calculate the energy required to remove the electron from a hydrogen atom in the n = 11 state, the formula below is used:

$E_n = \frac{E_0 × Z^{2}}{n^{2}}$

where

$E_0 \: is \: ground \: state \: energy \: of \: hydrogen \: atom \: = -13.6 eV \\$

Z = 1
n = 11

substituting the values:

$E_n = \frac{ - 13.6 × 1^{2}}{11^{2}} \: = - 0.112 \: eV$

Therefore, the energy required to remove an electron from a hydrogen atom in the n = 11 state is -0.112 eV

Learn more about ionization energy at: brainly.com/question/1445179

5 0

2 years ago

8.

kipiarov [429]

Answer:

Mitosis takes place in four stages: prophase (sometimes divided into early prophase and prometaphase), metaphase, anaphase, and telophase. You can learn more about these stages in the video on mitosis. In cytokinesis, the cytoplasm of the cell is split in two, making two new cells.

3 0

3 years ago

Suppose that 0.25 mole of gas C was added to the mixture without changing the total pressure of the mixture. How does the additi

Yanka [14]

Here we have to get the effect of addition of 0.25 moles of gas C on the mole fraction of gas A in a mixture of gas having constant pressure.

On addition of 0.25 moles of C gas, the mole fraction of gas A will be $\frac{moles of gas A}{moles of gas A + 0.25}$ .

The partial pressure of gas A can be written as $P_{A}$ = $x_{A}$ ×P (where $x_{A}$ is the mole fraction of gas A present in the mixture and P is the total pressure of the mixture.

The mole fraction of gas A in a mixture of gas A and C is = $\frac{moles of gas A}{moles of gas A + moles of gas C}$ and $\frac{moles of gas C}{moles of gas A + moles of gas C}$ respectively.

Thus on addition of 0.25 moles of C gas, the mole fraction of gas A will be $\frac{moles of gas A}{moles of gas A + 0.25}$ .

Which is different from the initial state.

4 0

3 years ago

Read 2 more answers