What is the pH of a solution prepared by dissolving0.8 g NaOH in water to make 200 mL solution?

Chemistry

2 answers:

Effectus [21]3 years ago

6 0

Answer:

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What is the pH of a solution prepared by dissolving

0.8 g NaOH in water to make 200 mL solution?

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pH>7

Bases tend to increase the pH of a solution.Since,water has the pH of 7 and NaOH has pH of 14, the overall pH of solution will increase.

Ad libitum [116K]3 years ago

3 0

Answer:

pH>7

Explanation:

bases tend to increase the pH of a solution. since water has the pH of 7 and NaOH has pHof 14, the overall pH of solution will increase.

hope it's helpful.

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An acid with molar mass 84.48 g/mol is titrated with 0.650 M KOH. What volume of KOH solution is needed to titrate 1.70 grams of

RSB [31]

Answer:

$V=0.0310L=3.10mL$

Explanation:

Hello.

In this case, since the acid is monoprotic and the KOH has one hydroxyl ion only, we can see that at the equivalence point the moles of both of them are the same:

$n_{acid}=n_{KOH}$

Thus, since we are given 1.70 g of the acid, we compute the moles of acid that were titrated:

$n_{acid}=1.70g*\frac{1mol}{84.48g}=0.0201mol$

Which equal the moles of KOH. In such a way, since the molarity is defined as moles over liters (M=n/V), the liters are moles over molarity (V=n/M), thus, the resulting volume is:

$V=\frac{0.0201mol}{0.650mol/L}\\\\V=0.0310L=3.10mL$