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Serjik [45]
3 years ago
14

3SO2 + 2HNO3 + 2H2O → 3H2SO4 + 2NO Which statement is true about this chemical equation? H (hydrogen) was oxidized and S (sulfur

) was reduced. H (hydrogen) was reduced and N (nitrogen) was oxidized. S (sulfur) was oxidized and N (nitrogen) was reduced. S (sulfur) was reduced and N (nitrogen) was oxidized.
Chemistry
1 answer:
Klio2033 [76]3 years ago
7 0

Answer:

S (sulfur) was oxidized and N (nitrogen) was reduced.

Explanation:

In order to determine which element was oxidized or reduced in the equation, the change in the oxidation number of the element is observed.

Increase in oxidation number refers to oxidation and decrease in oxidation number refers to reduction

3SO2 + 2HNO3 + 2H2O → 3H2SO4 + 2NO

Sulphur;

Reactant side: +4

Product side: +6

This means there was a decrease in oxidation number. Sulfur was oxidized

Nitrogen;

Reactant side: +5

Product side: +2

This means there was a decrease in oxidation number. Nitrogen was reduced

Hydrogen and Oxygen both have a fixed oxidation number!

The correct option is;

S (sulfur) was oxidized and N (nitrogen) was reduced.

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You are given the following information: mass = 48 g; volume=24 cm. What is the density of this substance?
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Answer:

Density = 0.0035 g/cm³

Explanation:

The density equation looks like this:

Density (g/cm³) = mass (g) / volume (cm³)

You have been given both the mass and volume. However, the given volume is not in the correct units. To convert cm to cm³, you should simply raise the given volume to the power of 3.

24 cm  =  (24 cm)³  =  24³cm³  =  13,834 cm³

Now, you can plug you mass and volume into the equation and solve for density. The final answer should have 2 sig figs to reflect the given values.

Density = mass / volume

Density = 48 g / 13,824 cm³

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