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geniusboy [140]
4 years ago
12

Julia and Kajal make deliveries on their bicycles. For each delivery, they need some time to get ready, and then they each ride

at a constant speed.
Julia takes 40 minutes to make a delivery 5 kilometers away. She uses 10 minutes of the delivery time to get ready

The time it takes Kajal to make a delivery (in minutes) as a function of the distance of the delivery (in kilometers) is given by the following function:

T(d)=15+6d

Who takes more time to get ready?

Who rides faster?
Mathematics
1 answer:
UNO [17]4 years ago
5 0

For Julia’s case, we determine first he time it takes her to ride or cover every kilometre knowing that 10 minutes of the given 40 minutes is used for the preparation.

 

<span>    r (Julia) = (40 – 10 min) / 5 km = 6 minutes per kilometre</span>

 

<span>A.    </span>The time it takes Julia to get ready is only 10 minutes while from the given equation, the time it takes Kajal to get ready is 15 minutes. Hence, the answer is Kajal.

<span>B.    </span><span>From the calculation above, it takes Julia 6 minutes to cover a kilometre. From the equation, it is also given that Kajal takes 6 minutes to cover every kilometre. Hence, the answer is Neither as they travel at the same rate. </span>

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Consider testing H^0: u=20 against H^a: u&lt;20 where u is the mean number of latex gloves used per week by all hospital employe
iragen [17]

Answer:

Part a: P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=46-1=45  

Since is a one sided test the p value would be:  

p_v =P(t_{(45)}  

Part b: Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, and we can conclude that the true mean is not lower than 20 at 1% of signficance.  

a. There is insufficient evidence to reject h^0

Step-by-step explanation:

Data given and notation  

\bar X=19.1 represent the sample mean

s=11.8 represent the sample standard deviation

n=46 sample size  

\mu_o =20 represent the value that we want to test

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is lower than 20, the system of hypothesis would be:  

Null hypothesis:\mu \geq 20  

Alternative hypothesis:\mu < 20  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{19.1-20}{\frac{11.8}{\sqrt{46}}}=-0.517    

Part a: P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=46-1=45  

Since is a one sided test the p value would be:  

p_v =P(t_{(45)}  

Part b: Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, and we can conclude that the true mean is not lower than 20 at 1% of signficance.  

a. There is insufficient evidence to reject h^0

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Help ASAP please!!
Anit [1.1K]

Answer: The distance between W and X

if it helps, jump from the dash under W to the next dash until you get to X, you'll get 5 units

Hope this helps you and I hope you have a nice day :)

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