Answer:
NaOH: 22.99 + 16.00 + 1.008 = 40.00 g/mol
H₂O: 2(1.008) + 16.00 = 18.02 g/mol
C₆H₁₂O₆: 6(12.01) + 12(1.008) + 6(16.00) = 180.2 g/mol
CaSO₄: 40.08 + 32.06 + 4(16.00) = 136.1 g/mol
Mg₃(PO₄)₂: 3(24.33) + 2(30.97) + 8(16.00) = 262.9 g/mol
The numbers I added up are the atomic numbers you can find on the periodic table. Multiply the atomic numbers by however many atoms of a element you have.
Answer:
1.788 × 10⁷ g
Explanation:
Let's consider the following balanced equation.
2 H₂ + O₂ → 2 H₂O
We can establish the following relations.
- The molar mass of H₂ is 2.016 g/mol.
- The molar ratio of H₂ to H₂O is 2:2.
- The molar mass of H₂O is 18.02 g/mol.
The mass of H₂O obtained from 200.0 kg (200.0 × 10³ g = 2.000 × 10⁶ g) of H₂ is:
Answer:
- 0.0413°C ≅ - 0.041°C (nearest thousands).
Explanation:
- Adding solute to water causes the depression of the freezing point.
<em>ΔTf = Kf.m,</em>
Where,
ΔTf is the change in the freezing point.
Kf is the freezing point depression constant (Kf = 1.86 °C/m).
m is the molality of the solution.
<em>Molality is the no. of moles of solute per kg of the solution.</em>
- <em>no. of moles of solute (glucose) = mass/molar mass</em> = (8.44 g)/(180.156 g/mol) = <em>0.04685 mol.</em>
<em>∴ molality (m) = no. of moles of solute/kg of solvent</em> = (0.04685 mol)/(2.11 kg) = <em>0.0222 m.</em>
∴ ΔTf = Kf.m = (1.86 °C/m)(0.0222 m) = 0.0413°C.
<em>∴ The freezing point of the solution = the freezing point of water - ΔTf </em>= 0.0°C - 0.0413°C = <em>- 0.0413°C ≅ - 0.041°C (nearest thousands).</em>
The B. Ca-F pair has the greatest electronegativity difference.
Electronegativities <em>increase from the lower left to the upper right</em> in the Periodic Table.
Ca is closest to the lower left, and F is in the upper right, so the Ca-F bond has the greatest electronegativity difference.
Answer:
It is not possible
Explanation:
Nitrogen is a light gas that find application in my areas including being used to keep things cold.It has a freezing point of -210°c so the scientist Nitrogen in the question at 100°c have already freezed and no longer a liquid.
