Answer:
These particles were considered so small that they were unable to be cut
Answer:
Explanation:
First, we need to find the molecular mass of water (H₂O).
H₂O has:
- 2 Hydrogen atoms (subscript of 2)
- 1 Oxygen atom (implied subscript of 1)
Use the Periodic Table to find the mass of hydrogen and oxygen. Then, multiply by the number of atoms of the element.
- Hydrogen: 1.0079 g/mol
- Oxygen: 15.9994 g/mol
There are 2 hydrogen atoms, so multiply the mass by 2.
- 2 Hydrogen: (1.0079 g/mol)(2)= 2.0158 g/mol
Now, find the mass of H₂O. Add the mass of 2 hydrogen atoms and 1 oxygen atom.
- 2.0158 g/mol + 15.9994 g/mol = 18.0152 g/mol
Next, find the amount of moles using the molecular mass we just calculated. Set up a ratio.
Multiply. The grams of H₂O will cancel out.
The original measurement given had two significant figures (3,2). We must round to have 2 significant figures. All the zeroes before the 1 are not significant. So, round to the ten thousandth.
The 7 in the hundred thousandth place tells us to round up.
There are about <u>0.0018 moles in 0.032 grams.</u>
0.66 M is the accurate molarity of the new solution of volume of 1200 ml.
Explanation:
Data given:
molarity of copper(II) sulphate, Mconc.= 2M
volume of 2M solution taken Vconc. = 400 ml
volume taken for dilution, Vdilute = 1200 ml
molarity of the diluted solution, Mdilute =?
We will use the formula for dilution as
Mconc Vconc = Mdilute x V dilute (conc is concentrated)
putting the values in the equation:
2 x 400 = Mdilute x 1200
Mdilute =
Mdilute = 0.66 M
When the solution is diluted to the volume of 1200 ml its molarity changes to 0.66 M.
Over the northern parts of the Pacific Ocean, the Maritime Polar air mass exists. This means that the air mass likely to be over the northern parts of the Pacific Ocean would be wet and cold.