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3 years ago

Would be glad if you helped me!

Chemistry

1 answer:

Sindrei [870]3 years ago

6 0

A) Fe⁰ ----> Fe⁺³ +3e⁻ oxidation | *2
b) Cu⁺² + 2e⁻ -----> Cu⁰ reduction |*3

c) 2Fe⁰ +3Cu⁺² -----> 2Fe⁺³ + 2Cu⁰

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Concentration is calculated as molarity, which is the number of moles per litre.

***Molarity is represented by either "M" or "c" depending on your teacher. I will use "c".

The formula for molarity is:

$c = \frac{n}{V}$

n = moles (unit mol)

V = volume (unit L)

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$M_{KOH} = \frac{39.098 g}{mol}+\frac{16.000 g}{mol}+\frac{1.008 g}{mol}$

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$n_{KOH} = 0.25941(9)mol$

Carry one insignificant figure (shown in brackets).

Convert the volume of water to litres.

$V = \frac{500.0mL}{1}*\frac{1L}{1000mL}$

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Here, carrying an insignificant figure doesn't change the value.

Calculate the concentration.

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$c = \frac{0.25941(9)mol}{0.5000 L}$

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The concentration of this standard solution is 0.5188 M.

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