Answer:
can you help mine please
How many molecules of chlorine are needed to react with 56.Og of iron to form Iron (III) chloride (FeCl3)?
<span>CH</span>₃<span>CH</span>₂<span>COOH + H</span>₂<span>O </span>↔ <span> CH</span>₃<span>CH</span>₂<span>COO</span>⁻<span> + H</span>₃<span>O</span>⁺<span>
</span>
pH = 0.5 pKa + 0.5 pCa
0.5 pCa = pH - 0.5 pKa
= 4.2 - (0.5 * (-log 1.34 x 10⁻⁵)) = 1.76
pCa = 3.53
Ca = antilog - 3.52 = 3 x 10⁻⁴
where Ca is the acid concentration
SI unites are based on multiplying or dividing by 10, 100, 1,000, 10,000 (and so on...) depending on the unit you're solving for.
Answer: single covalent bond
Explanation: Chlorine is a simple molecule. each chlorine atom can count 8 electrons in its outer shell. with other chlorine atoms. One pair of shared electrons form a single covalent bond.
<span> the line-emission spectrum of an atom is caused by the energies released when electrons. releases energy of only certain values. </span>
