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Arte-miy333 [17]
3 years ago
10

Due to the doppler effect when moving away from the source of a sound

Physics
1 answer:
Ray Of Light [21]3 years ago
5 0
You do not hear it as clearly as you did, the frequency goes down. Likewise, if you moved closer you would hear it more.
You might be interested in
Please help<br>Will give the brainliest!​
Ronch [10]

Answer:

both answer is option C

Explanation:

tag me brainliest

7 0
3 years ago
HELP ASAP!!!
butalik [34]

Answer:

<em>D. The acceleration after it leaves the hand is 10 m/s/s downwards </em>

Explanation:

<u>Vertical Throw </u>

When an object is thrown upwards, it describes a special type of motion ruled only by gravity.  

When the ball is launched, it has its maximum speed upwards. The acceleration of gravity is always the same because it's a constant value near our planet's surface. The object starts to lose speed since the acceleration of gravity is pointed downwards and makes the object stop in the mid-air at its maximum height, where the speed is zero. Then, the object starts to fall and regain speed, this time downwards until it reaches back the launching point at the very same speed it was launched, but in the opposite direction.

The time it takes to reach its maximum height is the same it takes to return to the catching point, 2 seconds later.  

With all these concepts in mind, we state that:

<em>D. The acceleration after it leaves the hand is 10 m/s/s downwards  </em>

The other options are not correct   because:

A. The acceleration is never upwards  

B. The acceleration is never 0  

C. Both times are equal

8 0
3 years ago
An arrow of 43 g moving at 84 m/s to the right, strikes an apple at rest. The arrow sticks to the apple and both travel at 16.8
Aloiza [94]

Answer:

<em>The mass of the apple is 0.172 kg (172 g)</em>

Explanation:

<u>The Law Of Conservation Of Linear Momentum </u>

The total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and speed v is  

P=mv.  

If we have a system of two bodies, then the total momentum is the sum of both momentums:

P=m_1v_1+m_2v_2

If a collision occurs and the velocities change to v', the final momentum is:

P'=m_1v'_1+m_2v'_2

Since the total momentum is conserved, then:

P = P'

Or, equivalently:

m_1v_1+m_2v_2=m_1v'_1+m_2v'_2

If both masses stick together after the collision at a common speed v', then:

m_1v_1+m_2v_2=(m_1+m_2)v'

We are given the mass of an arrow m1=43 g = 0.043 kg traveling at v1=84 m/s to the right (positive direction). It strikes an apple of unknown mass m2 originally at rest (v2=0). The common speed after they collide is v'=16.8 m/s.

We need to solve the last equation for m2:

m_2v_2-m_2v'=m_1v'-m_1v_1

Factoring m2 and m1:

m_2(v_2-v')=m_1(v'-v_1)

Solving:

\displaystyle m_2=\frac{m_1(v'-v_1)}{v_2-v'}

Substituting:

\displaystyle m_2=\frac{0.043(16.8-84)}{0-16.8}

\displaystyle m_2=\frac{-2.8896}{-16.8}

\displaystyle m_2=0.172\ kg

The mass of the apple is 0.172 kg (172 g)

3 0
3 years ago
6.
Vikentia [17]

Answer:

Explanation:

Givens

vi = 0

a = 9.81

d = 4.50 m

vf = ?

Formula

vf^2 = vi^2 + 2 * a * d

Solution

Substitute the knowns into the formula

vf^2 =0 +  2 * 9.81 * 4.50

vf^2 = 88.29                          Take the square root of both sides.

sqrt(vf^2) = sqrt(88.29)    

vf = 9.40 m/s

3 0
3 years ago
What did Rutherford’s model of the atom include that Thomson’s model did not have?
Leona [35]
Rutherford tested Thomson'shypothesis by devising his "gold foil" experiment. Rutherford was forced to discard the Plum Pudding modeland reasoned that the only way the alpha particles could be deflected backwards was if most of the mass in an atom was concentrated in a nucleus.
6 0
3 years ago
Read 2 more answers
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