Answer:
current volume of the water = 785.714 in²
Height of new container = 10 inches
Step-by-step explanation:
Radius of the container = 5 inches
Height of the container = 20 inches
Volume of the container = πR²H = (22/7) × 5² × 20 = 1571.428571428 in²
Since the container is half filled with water, volume of the water = 1571.428571428 ÷ 2 = 785.714 in²
b. Volume of cylinder = πR²H = volume of water from first container = 785.714 in²
Hence 785.714 = (22/7) × 5² × H
H = (785.714) ÷ [(22/7) × 25] = 10 inches
Height of new container = 10 inches
To solve/simplify this all you have to do is group like terms (the x^2's with each other, the x's with each other, and the normal numbers, -8)
14x^2-8+5x-6x^2+2x
group the x^2 (add 14x^2 to -6x^2)
8x^2-8+5x+2x
group the x's together (add 5x and 2x together)
8x^2+7x-8
Your answer will be d) 8x^2+7x-8
A:line and a prism.
B:line and rectangle
Answer:
= 15/4 as fraction
Step-by-step explanation:
Y=(1/5)^x would be the only equation demonstrating decay of these
