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allsm [11]
3 years ago
9

Isabella is deciding between two parking garages. Garage A charges an initial fee of

Mathematics
1 answer:
bearhunter [10]3 years ago
7 0

Answer:

i. A = 4 + 3t .......... 1

  B = 12 + 2t .......... 2

ii. The hours required would be 8 hours.

Step-by-step explanation:

The charges at each of the garages can be expressed as;

i. For garage A,

A = 4 + 3t .......... 1

ii. For garage B,

B = 12 + 2t .......... 2

where A is the amount charged at garage A, B is the amount charged at garage B, and t is the number of hours.

To determine the number of hours  parked that would make the cost of each garage the same.

Let:

equation 1 = equation 2

4 + 3t = 12 + 2t

collect like terms

3t - 2t = 12 - 4

t = 8

The hours that would make the cost of each garage the same is 8 hours.

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Firdavs [7]

Answer:

Option d) 115 degrees

Step-by-step explanation:

We are given a trapezium ABDE in the picture.  AB and ED are the parallel sides.

F is the mid point of AE and C the midpoint of BD.  FC is joined.

We are also given that angle of AED = 65 degrees.

To find the measure of angle BAE.

Since sides AB and ED are parallel sides we find that AE is the transvesal intersecting the two parallel lines.

Hence by parallel lines axiom, the two interior angles namely Angle AED and BAE are supplementary.

i.e. 65 +angle BAE=180

Hence angle BAE = 115 degrees.

Option d is the answer.

7 0
3 years ago
Need the answer quick
Alchen [17]

Answer:

40 cm

Step-by-step explanation:

This is because the angle opposite the x is equal to the angle opposite the 40 cm making the sides equal as well.

6 0
3 years ago
A school is having a valentine's day sale. The first day,they sold 20 roses and 15 boxes of chocolate for $80. The second day th
True [87]

Answer:

roses were $1 each and chocolates were $4 per box

Step-by-step explanation:

let Cost of 1 rose = "R" and Cost of 1 box of chocolate = "C"

First day: cost of 20 roses + cost of 15 chocolate = $80,

or...

20R + 15C = 80  (divide both sides by 5)

4R + 3C = 16 ------------(eq 1)

Second day: cost of 40 roses + cost of 20 chocolate = $120,

or...

40R + 20C = 120  (divide both sides by 10)

4R + 2C = 12 ------------(eq 2)

by elimination, (eq 1) - (eq 2)

(4R + 3C) - (4R + 2C) = 16 - 12

4R + 3C - 4R - 2C = 4

C = 4  (substitute this back into eq 1)

4R + 3(4) = 16

4R + 12 = 16

4R = 16 - 12

4R = 4

R = 1

Hence roses were $1 each and chocolates were $4 per box

5 0
3 years ago
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seraphim [82]

Answer:

b. (1, 13).

Step-by-step explanation:

Here's a pic of my work. You can put either equation on the other side of the equal sign, because they both equal Y. therefore, they equal each other.

5 0
3 years ago
Read 2 more answers
Can somebody plz answer these questions correctly thanks!!
nadya68 [22]

Answer:

The decimal form of 3/5 is .6 or .60 and the percent form is 60%.

The fraction form of 0.3 is 30/100 or 3/10 and the percent form is 30%.

The decimal form of 3/20 is .15 and the percent form is 15%.

The fraction form of 0.58 is 58/100 or 29/50 and the percent form is 58%.

The decimal form of 19/50 is .38 and the percent form is 38%

4 0
3 years ago
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