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Step2247 [10]
3 years ago
14

the resistivity of a given wire of cross session area 0.7mm² is 49×10⁴.calcuate the resistance of a 2m lenght of wire​

Physics
1 answer:
sp2606 [1]3 years ago
6 0

R = 1.4GΩ.

The relation between the resistance and the resistivity is given by the equation R = ρL/A, where ρ is the resistivity of a given material, L is the length and A is the cross-sectional area of the material.

To calculate the resistance of a wire of L = 2m, ρ = 49x10⁴Ω.m and A = 0.7mm² = 0.7x10⁻³m² we have to use the equation  R = ρL/A.

R = [(49x10⁴Ω.m)(2m)/0.7x10⁻³m²

R = 98x10⁴Ω.m²/0.7x10⁻³m²

R = 1.4x10⁹Ω = 1.4GΩ

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An object is given a very small amount of charge. Which of the following could
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5.4*10^-19 C

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If you divide every other option listed by the charge of an electron, you will get an integer number.

(16*10^-19 C)/(1.6*10^-19C) = 10

(-6.4*10^-19 C)/(1.6*10^-19C) = -4

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Point charges of 21.0 μC and 47.0 μC are placed 0.500 m apart. (a) At what point (in m) along the line connecting them is the el
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Answer:

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FROM FIGURE

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