Prototype
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This room is called Substation
The solution for this problem is:
r = [(2.90 + 0.0900t²) i - 0.0150t³ j] m/s²
this is for t in seconds and r in meters
v = dr/dt = [0.180t i - 0.0450t² j] m/s²
tan(-36.0º) = -0.0450t² / 0.180t
0.7265 = 0.25t
t = 2.91 s is the velocity vector of the insect
The time elapsed since you stopped the stopwatch is 0.41 s.
<em>Your question is not complete, it seems to be missing the following information;</em>
"The velocity of the ant is 2 m/s"
The given parameters;
- velocity of the ant, v = 2 m/s
- change in position of the ant, Δx = 0.81 m
- time when the ant was noticed, = t₂
Velocity is defined as the change in displacement per change in time of motion of an object.

The time elapsed since you stopped the stopwatch is calculated as;

Thus, the time elapsed since you stopped the stopwatch is 0.41 s.
Learn more here: brainly.com/question/18153640
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