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3 years ago

Under which condition does a light ray striking a concave mirror reflect off parallel to the principle axis ?

Physics

2 answers:

asambeis [7]3 years ago

5 0

The answer would be c if u need to know

OleMash [197]3 years ago

4 0

Answer:

When the incident ray passes through the focal point

Explanation:

A concave mirror has an inward curved surface that reflects the light making it converge at a focal point. It is characterized by the fact that, unlike convex mirrors, concave mirrors show images of different shapes depending on the distance between the object and the mirror.

When the object is at the same focal point, the reflected rays are parallel and never cross, so no image is formed, or in other words, it is reflected parallel to the main axis.

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If two bicycles of same masses move at different velocities,it will be easier to stop the bicycle that is moving at lower veloci

s344n2d4d5 [400]

Answer:

It is easier to stop the bicycle moving at a lower velocity because it will require a smaller force to stop it when compared to a bicycle with a higher velocity that needs a bigger force.

Explanation:

The question above is related to "Newton's Law of Motion." According to the Third Law of Motion, whenever an object exerts a force on another object (action force), an equal force is exerted against it. This force is of the same magnitude but opposite direction.

When it comes to moving bicycles, the force that stops their movement is called "friction." Applying the law of motion, the higher the speed, the higher the force that is needed to stop it while the lower the speed, the lower the force that is needed to stop it.

8 0

3 years ago

True or False?

Goshia [24]

Answer:

the anwer is true , because production will decrease

8 0

3 years ago

Determine the magnitude of the resultant force acting on a 5 −kg particle at the instant t=2 s, if the particle is moving along

Alex787 [66]

Answer:

F = 296.7N

Explanation:

The x and y component of the position vector are given by:

$x(t) =rcos\phi, y(t) = rsin\phi\\ \frac{dx}{dt} =\frac{dr}{dt} cos\phi - rsin\phi\frac{d\phi}{dt} , \frac{dy}{dt}=\frac{dr}{dt}sin\phi + rcos\phi\frac{d\phi}{dt}\\ \frac{d^2x}{dt^2} = \frac{d^2r}{dt^2} cos\phi - \frac{dr}{dt} sin\phi\frac{d\phi}{dt} -\frac{dr}{dt} sin\phi\frac{d\phi}{dt} - r(cos\phi\frac{d^2\phi}{dt^2} + sin\phi\frac{d^2\phi}{dt^2})$

$\frac{d^2y}{dt^2} = \frac{d^2r}{dt^2} sin\phi + \frac{dr}{dt} cos\phi\frac{d\phi}{dt}+\frac{dr}{dt}cos\phi\frac{d\phi}{dt}+r(-sin\phi\frac{d^2\phi}{dt^2} +cos\phi\frac{d^2\phi}{dt^2})$

At t = 2s:

$\phi(2) = 1.5t^2-6t= -6\\ \frac{d\phi}{dt}(2) = 3t-6=0\\ \frac{d^2\phi}{dt^2}=3\\r(2)=2t+10=14\\ \frac{dr}{dt}=2\\\frac{d^2r}{dt^2} = 0$

Plugging in:

$\frac{d^2x}{dt^2}=-42(cos(-6) + sin(-6))=-52\frac{m}{s^2} \\\frac{d^2y}{dt^2} = 42(cos(-6)-sin(-6))=28.6\frac{m}{s^2}$

The resulting force F is:

$F = m\sqrt{(\frac{d^2x}{dt^2})^2 + (\frac{d^2y}{dt^2})^2}=296.7N$

5 0

3 years ago

Letting a = red spheres and b = blue spheres, write a balanced equation for the reaction. express your answer as a chemical equa

GenaCL600 [577]

Knowing that the a and b represents red and blue spheres respectively.The chemical equation we could make isL5A2 + 5B --> 4A2B + A2 + B as shown in boxes
Simplifying this would make it:
4A2 + 4B --> 4A2B
Thus, reducing the coefficients, the final answer is:
A2 + B --> A2B

5 0

3 years ago

Read 2 more answers

Which is not a step in the scientific method?

tensa zangetsu [6.8K]

A. Ask other people for their opinion. :)

5 0

3 years ago