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3 years ago

Under which condition does a light ray striking a concave mirror reflect off parallel to the principle axis ?

Physics

2 answers:

asambeis [7]3 years ago

5 0

The answer would be c if u need to know

OleMash [197]3 years ago

4 0

Answer:

When the incident ray passes through the focal point

Explanation:

A concave mirror has an inward curved surface that reflects the light making it converge at a focal point. It is characterized by the fact that, unlike convex mirrors, concave mirrors show images of different shapes depending on the distance between the object and the mirror.

When the object is at the same focal point, the reflected rays are parallel and never cross, so no image is formed, or in other words, it is reflected parallel to the main axis.

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The current theory of the structure of the

Mariana [72]

Answers:

a) $2.82(10)^{21} kg$

b) $1410 J$

c) $36.62 m/s$

Explanation:

<h3>a) Mass of the continent</h3>

Density $\rho$ is defined as a relation between mass $m$ and volume $V$ :

$\rho=\frac{m}{V}$ (1)

Where:

$\rho=2720 kg/m^{3}$ is the average density of the continent

$m$ is the mass of the continent

$V$ is the volume of the continent, which can be estimated is we assume it as a a slab of rock 5300 km on a side and 37 km deep:

$V=(length)(width)(depth)=(5300 km)(5300 km)(37 km)=1,030,330,000 km^{3} \frac{(1000 m)^{3}}{1 km^{3}}=1.03933(10)^{18} m^{3}$

Finding the mass:

$m=\rho V$ (2)

$m=(2720 kg/m^{3})(1.03933(10)^{18} m^{3})$ (3)

$m=2.82(10)^{21} kg$ (4) This is the mass of the continent

<h3>b) Kinetic energy of the continent</h3>

Kinetic energy $K$ is given by the following equation:

$K=\frac{1}{2}mv^{2}$ (5)

Where:

$m=2.82(10)^{21} kg$ is the mass of the continent

$v=4.8 \frac{cm}{year} \frac{1 m}{100 cm} \frac{1 year}{365 days} \frac{1 day}{24 hours} \frac{1 hour}{3600 s}=1(10)^{-9} m/s$ is the velocity of the continent

$K=\frac{1}{2}(2.82(10)^{21} kg)(1(10)^{-9} m/s)^{2}$ (6)

$K=1410 J$ (7) This is the kinetic energy of the continent

<h3>c) Speed of the jogger</h3>

If we have a jogger with mass $m=77 kg$ and the same kinetic energy as that of the continent $1413 J$ , we can find its velocity by isolating $v$ from (5):

$v=\sqrt{\frac{2 K}{m}}$ (6)

$v=\sqrt{\frac{2 (1413 J)}{77 kg}}$

Finally:

$v=36.62 m/s$ This is the speed of the jogger

5 0

3 years ago

A 30kg mass is brought from the earth to the moon what is the weight on the earth

ozzi

Answer:

Solution

verified

Verified by Toppr

Given:

Mass of body = 30 kg

gravitational acceleration on the moon = 1.62 m/s

Weight of the body on the moon = Mass of the body×gravitational acceleration on the moon=30×1.62=48 N

8 0

2 years ago

What is the function of the wire in

Naily [24]

Answer:

I think the right answer is option B.

3 0

3 years ago

A fish can travel 30km/h in still water. How long will it take to arrive 12km downstream in a river flowing 6km/h?

kodGreya [7K]

30 + 6 = 36

36/12 = 3

So, it would take it 3 hours to go 12 kms downstream.

Note that we added 30 and 6 because it was going downstream. If it was going upstream, then we would have had to subtract.

8 0

3 years ago

Objects that rest have no forces upon them

Pani-rosa [81]

Answer:

false

Explanation:

every object will always have the force of gravity acting upon it.

6 0

2 years ago