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3 years ago

6

Under which condition does a light ray striking a concave mirror reflect off parallel to the principle axis ?

2 answers:

asambeis [7]3 years ago

5 0

The answer would be c if u need to know

OleMash [197]3 years ago

4 0

Answer:

When the incident ray passes through the focal point

Explanation:

A concave mirror has an inward curved surface that reflects the light making it converge at a focal point. It is characterized by the fact that, unlike convex mirrors, concave mirrors show images of different shapes depending on the distance between the object and the mirror.

When the object is at the same focal point, the reflected rays are parallel and never cross, so no image is formed, or in other words, it is reflected parallel to the main axis.

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The proper mean lifetime of a muon is 2.2 × 10–6 s. A beam of muons is moving with speed 0.6c relative to an inertial observer.

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This might help you out

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3 years ago

Vector A is added to a second vector B which has an x-component of 3 m and a y- component of -5 m. The resultant (A + B) is in t

AlladinOne [14]

Answer:

Explanation:

As B has a y component of -5, A must have a y component of 5 to have the result lie on the x axis.

As B has an x component of 3 and the result has an x component of -4, A must have an x component of -7

A = (-7, 5)

magnitude A = √(7² + 5²) = √74 ≈ 8.60

θ = arctan(y/x) = arctan(5/-7) ≈ 144.46° CCW from the positive x axis

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2 years ago

Two cars travel in the same direction along a straight highway, one at a constant speed of 55 mi/h and the other at 60 mi/h.How

Pachacha [2.7K]

Answer:

The distance traveled by the faster car when it is 15 mins ahead of the slower car is 165 miles.

Explanation:

Given;

speed of the faster car, v₁ = 60 mi/h

speed of the slower car, v₂ = 55 mi/h

Let the distance traveled by the faster car when it is 15 mins ahead of the slower car = x miles

$\frac{x}{55} - \frac{x}{60} = \frac{15}{60}$

Note: divide 15 mins by 60 to convert to hours for consistency in the units.

$\frac{x}{55} - \frac{x}{60} = \frac{15}{60}\\\\multiple \ through \ by \ 660\\\\12x - 11x = 165\\\\x = 165 \ miles$

Therefore, the distance traveled by the faster car when it is 15 mins ahead of the slower car is 165 miles.

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3 years ago

Answer the following. (a) What is the surface temperature of Betelgeuse, a red giant star in the constellation of Orion, which r

bagirrra123 [75]

Answer:

(a) T = 2987.6 k

(b) T = 19986.2 k

Explanation:

The temperature of a star in terms of peak wavelength can be given by Wein's Displacement Law, which is as follows:

$T = \frac{0.2898\ x\ 10^{-2}\ m.k}{\lambda_{max}}$

where,

T = Radiated surface temperature

$\lambda_{max}$ = peak wavelength

(a)

here,

$\lambda_{max}$ = 970 nm = 9.7 x 10⁻⁷ m

Therefore,

$T = \frac{0.2898\ x\ 10^{-2}\ m.k}{9.7\ x\ 10^{-7}\ m}$

<u>T = 2987.6 k</u>

(b)

here,

$\lambda_{max}$ = 145 nm = 1.45 x 10⁻⁷ m

Therefore,

$T = \frac{0.2898\ x\ 10^{-2}\ m.k}{1.45\ x\ 10^{-7}\ m}$

<u>T = 19986.2 k</u>

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2 years ago

Which of these events is an example of resonance?

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An opera singer breaks a thin glass with only the use of her high frequency voice

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3 years ago

Read 2 more answers