Would presume you are asked to find the volume, since there is no second volume.
By General Gas Law:
P₁V₁/T₁ = P₂V₂/T₂
1.6 * 168 /255 = 1.3*V₂/285
V₂ = 1.6 * 168 * 285 / (1.3*255)
V₂ = 231.095
Final volume ≈ 231 cm³
Answer:
11.515 Joule
Explanation:
Volume of aluminium = V = 4.89×10⁻³ m³
Coefficient of volume expansion for aluminum = α = 69×10⁻⁶ /°C
Initial temperature = 19.1°C
Final temperature = 357°C
Pressure of air = 1.01×10⁵ Pa
Change in temperature = ΔT= 357-19.1 = 337.9 °C
Change in volume
ΔV = αVΔT
⇒ΔV = 69×10⁻⁶×4.89×10⁻³×337.9
⇒ΔV = 114010.839×10⁻⁹ m³
Work done
W = PΔV
⇒W = 1.01×10⁵×114010.839×10⁻⁹
⇒W = 11.515 J
∴ Work is done by the expanding aluminum is 11.515 Joule
According to Edge, the answers is
<h3>3100 V</h3>
and
<h3>200v</h3>
Answer:
7.5 right?
Explanation: if im wrong shoot me
Answer:
<em>The drop voltage is 0.3 V</em>
Explanation:
Electromotive Force EMF
When connecting a battery of internal resistance Ri and EMF ε to an external resistance Re, the current through the circuit is:
The battery has an internal resistance of Ro=2 Ω, ε=24 V and is connected to an external resistance of Re=158 Ω. Thus, the current is:
i = 0.15 A
The drop voltage is the voltage of the internal resistance:
The drop voltage is 0.3 V
