T = 0.017 s
From the foot to the brain is almost the same as the height. We are not given the height of the woman, but to find "about" how much time, we need a height to work with.
She *could* be 1.7 m <- height = distance
Formula for speed, where k = speed, d = distance, t = time
k = d/t
Rearrange to solve for time:
t = d/k
Substitute known values:
t = (1.7 m) / (100 m/s)
Solve:
t = 0.017 s
Therefore, it takes about 0.017s for the impulse to travel from the foot to the brain.
Answer:
Explanation:
formula for the period of a satellite = 2π.
period of satellite A (Ta) = 2π.
period of satellite B (Tb) = 2π.
ratio of the periods of the satellites = (take note that π is shown as )
where
- Me = mass of the earth
- G = universal gravitational constant
- π = 3.142
- all the above are constants and cancel each since they are both at the numerator and denominator
- R = distance from the earth
the equation now becomes
=
- the velocity of a satellite = (take note that π is shown as )
- rearranging the above R = (take note that π is shown as )
- now substituting the above into the equation we have
= (take note that π is shown as )
2π will cancel itself from the numerator and denominator and we have
=
squaring both sides we have
=
now cross multiplying we have
from the question the velocity of satellite A is 3 times that of satellite B hence Va = 3Vb
Answer:
Looks like A but I'm not sure.
Explanation:
dont take my word for it I might be wrong
a) create an expression
for the ball's initial horizontal velocity, V0x, in terms of the variables
given in the problem statement.
v0x = vf * cos(Θf)
<span>
b) calculate the ball's initial vertical velocity, V0y, in
m/s</span>
v0x = 32.4m/s * cos(-25.5º)
= 29.2 m/s <span>
tanΘ = v1y / v0x → tan(-25.5) = v1y / 29.2m/s → v1y = -13.93
m/s
the vertical velocity when the ball was caught.
(v0y)² = (v1y)² + 2as = (-13.93m/s)² + 2 * 9.8m/s² * 5.5m = 301.78
m²/s²
v0y = 17.37 m/s
c) calculate the magnitude of the ball's initial velocity,
v0, in m/s</span>
v0 = sqrt (v0y^2 +
v0x^2)
v0 = sqrt (17.37^2 + 29.2^2)
m/s
v0 = 33.98 m/s
<span>
d) find the angle, theta0, in degrees above the horizontal at
which which the ball left the bat.</span>
tan Θ = v0y/v0x
<span>Θ = arctan(17.37/29.2) =
30.75º above horizontal</span>
-- The total distance between the towns = 460 km.
-- For the first 3 hours, he travels at an average speed of 60 km/hr. During that time, he covers (60 km/hr) x (3 hrs) = 180 km.
-- At that point, he still has (460km - 180km) = 280 km to go.
-- If he drives that 280km at an average speed of 70 km/hr, it'll take him (280km)/(70km/hr) = 4 hrs to cover it.
-- His total time for the whole trip is (3 hours for the first part) + (4 hours for the last part) = <em>7 hours</em>.