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Virty [35]
4 years ago
10

What will Al’s charge be when it comes an ion

Physics
1 answer:
kolbaska11 [484]4 years ago
5 0
The charge will be 3+
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A soccerball is kicked straight out from a hill at 15 m/s and lands 42m away. how tall is the hill
ozzi

Answer:

The height of the hill is, h = 38.42 m

Explanation:

Given,

The horizontal velocity of the soccer ball, Vx = 15 m/s

The range of the soccer ball, s = 42 m

The projectile projected from a height is given by the formula

                             S = Vx [Vy + √(Vy² + 2gh)] / g

Therefore,

                            h = S²g/2Vx²                     (Since Vy = 0)

Substituting the values

                             h = 42² x 9.8/ (2 x 15²)

                                = 38.42 m

Hence, the height of the hill is, h = 38.42 m

4 0
4 years ago
Could someone help me with some info for an essay?I WILL REPOST FOR 100 POINTS IF YOU CAN.
polet [3.4K]

Answer:

Self-motivation is the surest way to stay focused. Nearly all the most significant tasks in life are tests for our motivation. Facing challenges and achieving success requires focus; this means we need to be responsible for our motivation. People who are motivated towards achieving their goals are focused on success. The following ideas will help you stay focused and motivated in your work and studies.

Explanation:

3 0
3 years ago
Two identical soccer balls are rolled towards each other. What will be true after they collide head-on
tresset_1 [31]
They will go away from each other
8 0
4 years ago
Read 2 more answers
An ice skater accelerates backwards for 5.0 seconds to a final speed of 12 m/s. If the acceleration backwards was at a rate of 1
Lostsunrise [7]

Answer:

Vo = 4.5 [m/s]

Explanation:

In order to solve this problem, we must use the following equation of kinematics.

v_{f}=v_{o}+a*t

where:

Vf = final velocity = 12 [m/s]

Vo = initial velocity [m/s]

a = acceleration = 1.5 [m/s²]

t = time = 5 [s]

Now replacing:

12=v_{o}+1.5*5\\v_{o}=12- (7.5)\\v_{o}= 4.5[m/s]

4 0
3 years ago
A 50.0-kg block is being pulled up a 13.0° slope by a force of 250 N which is parallel to the slope, but the block does not slid
Elan Coil [88]

<span>Weight of block, Wb = mass*gravity = 50*9.8 = 490 N</span>

Since block is being pulled up by a 13-degree slope

Therefore, Force which is acting parallel to the slop:

<span> F p =490 Sin </span>13^{0}= 110.2N

Force which is acting perpendicular to the slope:

<span> Fv =490 Cos</span>13^{0} = 477.4 N

Net force can be given as follows:

<span>F n = (250 - 110.2 - 0.2*</span>477.4) N

<span>Fn=44.3N</span>

Now acceleration is given by the ratio of force to mass

<span>a = Fn/m</span>

<span>=44.3/50 = 0.89 ms^<span>-2</span></span>

8 0
3 years ago
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