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Virty [35]
3 years ago
10

What will Al’s charge be when it comes an ion

Physics
1 answer:
kolbaska11 [484]3 years ago
5 0
The charge will be 3+
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An object dropped on Planet P falls 144 m in 6 seconds. What is the gravitational acceleration of Planet P ? Gravitational accel
Tju [1.3M]

Answer:

The gravitational acceleration of the planet is, g = 8 m/s²

Explanation:

Given data,

The distance the object falls, s = 144 m

The time taken by the object is, t = 6 s

Using the III equations of motion

                  S = ut + ½ gt²

∴                 g = 2S/t²

Substituting the given values,

                   g = 2 x 144 /6²

                      = 8 m/s²

Hence, the gravitational acceleration of the planet is, g = 8 m/s²

7 0
3 years ago
Write down the boiling point and freezing point of mercury an alcohol​
nekit [7.7K]
Mercury has a high boiling point of 357 degrees C.
Mercury has a freezing point of −39 degrees C.
8 0
2 years ago
When grocery shopping, the mass of the cart changes as you start to fill up your cart. How does the change in mass of your cart
Tasya [4]

Answer:

b

Explanation:

4 0
3 years ago
Which graph shows the correct relationship between kinetic energy and speed?
Mamont248 [21]

Answer: D

Explanation:

Kinetic energy = 1/2mV^2

From the formula above, we can deduce that kinetic energy is proportional to the square of speed. That is,

K.E = V^2

Graphically, the relationship isn't linear but a positive exponential. Therefore, option D is the correct answer.

3 0
3 years ago
A horizontal 953 N merry-go-round of radius 1.68 m is started from rest by a constant horizontal force of 73.9 N applied tangent
solniwko [45]

Answer:

K.E=365.2 J

Explanation:

Given data

Weight w =953 N

radius r=1.68 m

F=73.9 N

t=2.55 s

g=9.8 m/s²

To find

Kinetic Energy K.E

Solution

From the moment of inertia

I=(1/2)MR^{2}\\ as \\W=mg\\So\\I=(1/2)(W/g)R^{2}\\I=(1/2)(953/9.8)(1.68)^{2}\\I=137.232kg.m^{2}

The angular acceleration is given as

a=T/I\\a=\frac{FR}{I}\\ a=\frac{(73.9)(1.68)}{137.232}\\a=0.905rad/s^{2}

The angular velocity is given as

w=at\\w=(0.905)(2.55)\\w=2.31rad/s

So the Kinetic Energy is given as

K.E=(1/2)Iw^{2}\\ K.E=(1/2)(137.232)(2.31)^{2}\\ K.E=365.2J

3 0
3 years ago
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