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2 years ago

A 15N block is sliding at constant speed across the frictionless floor of an ice rink.

Physics

1 answer:

Gnesinka [82]2 years ago

8 0

Answer:

so, why we have to find here..

<h3>stay safe healthy and happy.</h3>

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What is heat, and how does it affect the molecules<br> in a substance?

DaniilM [7]

Answer:

Heat is the form of energy which transfers from hotter body( high temperature) to colder body ( low temperature).

It increases the kinetic energy of molecules of the body.

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2 years ago

A resistor and an ideal inductor are connected in series to an ideal battery having a constant terminal voltage V 0. (a) At the

dybincka [34]

Answer:

the voltage across the resistor is V= 0

Explanation:

The correct answer is zero.

The answer is zero because the inductor acts as open circuit.

$i= i_0[1-e^{-\frac{t}{\tau} }]$

i_o= maximum current

\tau= L/R= time constant

i= current at any instant

$V= V_0[1-e^{-\frac{t}{\tau} }]$

at t=0 at the moment when contact is made

V=V_o[1-1]

⇒V= 0 V

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2 years ago

What are the three most influential variables that affect electrical force?

snow_tiger [21]

I know that the answer is 3 because 1+2 is 3

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3 years ago

Which of these diagrams most accurately illustrates what happens when a ray of light from underwater strikes the smooth surface

laiz [17]

Diagram D!!!!!!!!!!!!!!!

4 0

2 years ago

Read 2 more answers

In a World Cup soccer match, Juan is running due north toward the goal with a speed of 7.60 m/s relative to the ground. A teamma

spayn [35]

Answer:

Part a)

$v_{bj} = 11.03 m/s$

Part b)

$\theta = 4.57 degree$ East of South

Explanation:

Part a)

Velocity of Juan is given as

$v_1 = 7.60 m/s \hat j$

velocity of the ball is given as

$v_2 = 12.9(cos31.4 \hat i + sin31.4\hat j)$

now we have

$v_2 = 11\hat i + 6.72\hat j$

Part a)

We need to find velocity of ball with respect to Juan

so it is given as

$v_{bJ} = \vec v_b - \vec v_j$

$v_{bj} = 11\hat i + 6.72 \hat j - 7.6\hat j$

$v_{bj} = 11\hat i - 0.88\hat j$

magnitude of the speed is given as

$v_{bj} = \sqrt{11^2 + 0.88^2}$

$v_{bj} = 11.03 m/s$

Part b)

direction of velocity of the ball

$tan\theta = \frac{v_y}{v_x}$

$tan\theta = \frac{-0.88}{11}$

$\theta = 4.57 degree$ East of South

3 0

2 years ago