1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Leona [35]
3 years ago
10

A stunt man jumps from the top of a building and lands 10 meters below his initial height. In case A, the stunt man lands on a s

tack of foam mattresses. In case B, the stunt man lands on a stack of concrete blocks. In which case will the person be more likely to sustain serious injury?
Physics
1 answer:
krek1111 [17]3 years ago
8 0

Answer:

Explanation:

The stunt will likely sustain serious injury in case of concrete blocks because the average force acting on the person will be more because concrete blocks do not squeeze to provide more time for the force to act on the body instead it acts for a small amount of interval.

Impulse=F_{avg}\times \Delta T

As impulse is constant so time requires to act force on the body is more as compared to concrete block and thus average force in mattress case is less.  

You might be interested in
A force of 30 N is applied to an object with a mass of 15 kg. What is the resulting acceleration?
svet-max [94.6K]

Answer:

We know that Force = mass × acceleration

By substituting the values we get,

30 N = 15 kg × a (where a is acceleration)

Or we can write it as

15 kg × a = 30 N

Transposing 15 to RHS,

a = 30 ÷ 15 m/s²

Therefore, acceleration = 2 m/s²

pls give brainliest for the answer

5 0
2 years ago
Read 2 more answers
Calculate how much work is required to launch a spacecraft of mass mm from the surface of the earth (mass mEmE, radius RERE) and
SIZIF [17.4K]

Answer:

Work done = (1/2)[(Gmm_e)/(R_e)]

Explanation:

I've attached the explanations below.

5 0
3 years ago
Read 2 more answers
What changes a ball velocity
Grace [21]

Answer/Explanation: Speed and direction can change with time. When you throw a ball into the air, it leaves your hand at a certain speed. As the ball rises, it slows down. Then, as the ball falls back toward the ground, it speeds up again. When the ball hits the ground, its direction of motion changes and it bounces back up into the air.

5 0
3 years ago
Assume that the function x(t) represents the length of tape that has unwound as a function of time. find θ(t), the angle through
bekas [8.4K]
We know that arc length (x(t)) is given with the following formula:
x(t)=\theta(t) r
Where r is the radius of the barrel. We must keep in mind that as barrel rolls its radius decreases because less and less tape is left on it.
If we say that the thickness of the tape is D then with every full circle our radius shrinks by d. We can write this down mathematically:
r(\theta)=r_0-\frac{D\cdot \theta}{2\pi}
When we plug this back into the first equation we get:
x(t)=\theta(r_0-\frac{D\theta}{2\pi}})\\ \frac{D\theta^2}{2\pi}-\theta r_0+x(t)=0\\
We must solve this quadratic equation.
The final solution is:
\theta=\frac{\pi r_0+\sqrt{\pi \left(-2Dx(t)+\pi r_0^2\right)}}{D},\:\theta=\frac{\pi r_0-\sqrt{\pi \left(-2Dx(t)+\pi r_0^2\right)}}{D}
It is rather complicated solution. If we asume that the tape has no thickness we get simply:
x(t)=\theta(r_0-\frac{D\theta}{2\pi}});D=0\\
x(t)=\theta r_0\\
\theta(t)=\frac{x(t)}{r_0}

8 0
3 years ago
Consider two objects (Object 1 and Object 2) moving in the same direction on a frictionless surface. Object 1 moves with speed v
d1i1m1o1n [39]

1) A) Object 1 has the greater momentum

The magnitude of the momentum of an object is given by:

p=mv

where

m is the mass of the object

v is its speed

Object 1 has a mass of m_1 = 2m and a speed of v_1 = v, so its momentum is

p_1 = m_1 v_1 = (2m)(v)=2mv

Object 2 has a mass of m_2 = m and a speed of v_2 = \sqrt{2} v, so its momentum is

p_2 = m_2 v_2 = (m)(\sqrt{2} v)=\sqrt{2}mv

So we see that p_1 > p_2, so object 1 has the greater momentum.

2) The objects have the same kinetic energy.

The kinetic energy of an object is given by

K=\frac{1}{2}mv^2

where

m is the mass of the object

v is its speed

Object 1 has a mass of m_1 = 2m and a speed of v_1 = v, so its kinetic energy is

K_1 = \frac{1}{2}m_1 v_1^2 = \frac{1}{2}(2m)(v)^2=mv^2

Object 2 has a mass of m_2 = m and a speed of v_2 = \sqrt{2} v, so its kinetic energy is

K_2 = \frac{1}{2}m_2 v_2^2 = \frac{1}{2}(m)(\sqrt{2} v)^2=mv^2

So we see that K_1 =K_2, so the objects have same kinetic energy

5 0
3 years ago
Other questions:
  • PLEASE HELP
    5·1 answer
  • A length of copper wire has a resistance 29 Ω. The wire is cut into three pieces of equal length, which are then connected as pa
    6·1 answer
  • Two conductors are made of the same material and have the same length. Conductor A is a solid wire of diameter 2.0 mm. Conductor
    11·1 answer
  • An ocean liner is cruising at 10 meters/second and is about to approach a stationary ferryboat. A parcel is released from the oc
    9·1 answer
  • This person does work to stretch the rubber band. When will the potential energy be the greatest?
    5·1 answer
  • Explain why dogs pant during hot summer days using the evaporation concept?
    7·1 answer
  • A glass tube (open at both ends) of length L is positioned near an audio speaker of frequency f = 770 Hz. For what values of L w
    9·1 answer
  • The temperature of the air in a valley begins to increase after the sun comes up and heats the valley floor. What will
    8·1 answer
  • The farther away you are from a light source, the _____ intense it appears
    13·1 answer
  • What is the equivalent resistance?​
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!