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natita [175]
3 years ago
12

When a number is a multiple of 6, what are the possible values for the ones digits?

Mathematics
1 answer:
Liula [17]3 years ago
7 0
I would do this by first listing the multiples of 6 until I start to see a pattern with the one's digit.
6x0=0
6x1=6
6x2=12
6x3=18
6x4=24
6x5=30
6x6=36
6x7=42
6x8=48
...
The digits in bold are the one's digits so those are the only ones we really care about.  If you list just them it looks like: 0,6,2,8,4,0,6,2,8
Notice how the first set of 5 numbers seems as though it repeats in the 6th, 7th, and 8th numbers.  This probably means the pattern continues infinitely so the first 5 numbers are all the one's digits that can come from multiples of 6.  Thus your answer is: 0,6,2,8,or 4 
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-5x + 8y = -21<br> 3x - 4y = 15
fomenos

The value of x and y in the equation -5x + 8y = -21 and 3x - 4y = 15 are 9 and 4 respectively.

<h3>What is an equation?</h3>

An equation is the statement that illustrates that the variables given. In this case, two or more components are taken into consideration to describe the scenario. It is vital to note that an equation is a mathematical statement which is made up of two expressions that are connected by an equal sign.

The equation is given as:

-5x + 8y = -21

3x - 4y = 15

Multiply equation i by 3

Multiply equation ii by 5

-15x + 24y = -63

15x - 20y = 75

Add both equations

4y = 12

Divide

y = 12/4

y = 3

From 3x - 4y = 15

3x - 4(3) = 15

3x - 12 = 15

Collect like terms

3x = 12 + 15

3x = 27

Divide

x = 27/3

x = 9

Therefore, x = 9 and y = 4.

Learn more about equations on:

brainly.com/question/2972832

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