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3 years ago

Simplify the rational expression. 6x(x+3)(x - 2) 3(x - 2)(x+9)

Mathematics

2 answers:

il63 [147K]3 years ago

8 0

Answer: 2x(x+3)/(x+9)

Step-by-step explanation:

Murrr4er [49]3 years ago

4 0

Answer:

The first one is 6 x^ 3 + 6 x^ 2 - 36 x

and the second one is 3x^2 + 21x - 54

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3 years ago

A gym membership costs $25 to join and $14 each month. What is an algebraic expression to find the cost of the membership for 6

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3 years ago

Water boils at 100C which's 400% more than my room temperature. so what's my room temperature

zavuch27 [327]

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Step-by-step explanation:

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3 years ago

What sample size should be used if we would like to estimate the mean age of the college students at a particular campus with 95

nevsk [136]

Answer: 12

Step-by-step explanation:

The formula to find the sample size is given by:-

$n=(\dfrac{z_c\cdot \sigma}{E})^2$ , where $\sigma$ is the population standard deviation, $z_c$ is the z-value for the $(1-\alpha)$ confidence interval and E is the margin of error .

As per given , we have

Population standard deviation : $\sigma=5.1$

z-value for 95% confidence interval : $z_c=1.960$

Margin of error : E= 3

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3 0

3 years ago

Tomato as a taste modifier. Miraculin—a protein naturally produced in a rare tropical fruit—has the potential to be an alternati

telo118 [61]

Answer:

a) 0.033

b) 0.468

c) 100

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 105.3

Standard Deviation, σ = 8

The amount x of miraculin produced (measured in micro-grams per gram of fresh weight) had a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(x > 120)

$P( x > 120) = P( z > \displaystyle\frac{120 - 105.3}{8}) = P(z > 1.8375)$

$= 1 - P(z \leq 1.8375)$

Calculation the value from standard normal z table, we have,

$P(x > 120) = 1 - 0.967 = 0.033 = 3.3\%$

b) P(x between 100 and 110)

$P(100 \leq x \leq 110) = P(\displaystyle\frac{100 - 105.3}{8} \leq z \leq \displaystyle\frac{110-105.3}{8}) = P(-0.6625 \leq z \leq 0.5875)\\\\= P(z \leq 0.5875) - P(z \leq -0.6625)\\= 0.722 - 0.254 = 0.468 = 46.8\%$

$P(100 \leq x \leq 110) = 46.8\%$

c) P(x < a) = 0.25

$P( x \leq a) = P( z \leq \displaystyle\frac{a - 105.3}{8}) = 0.25$

Calculation the value from standard normal z table, we have,

$P( z \leq -0.674) = 0.25$

$\displaystyle\frac{x - 105.3}{8} = -0.674\\\\x = -0.674\times 8 + 105.3 = 99.908 \approx 100$

3 0

3 years ago