The length of the rectangle is 8cm longer than the width.
l=w+8
If the length of the original rectangle is increased by 6cm and the width is increased by 3cm the perimeter is 76cm.
p=76=((l+6)+(w+3))*2=(l+6+w+3)*2=(l+w+9)*2
to solve this substitute l=w+8 into the p= equation:
p=76=((w+8)+w+9)*2=
76=(2w+17)*2
76=4w+34
42=4w
10.5=w
l=w+8=10.5+8=18.5
Answer:
14
Step-by-step explanation:
Answer:
The correct option is B). 
Step-by-step explanation:
Given function is 
On simplifying,
=
=![[4x^{2}+16x+16]-(2x^{2} +6)](https://tex.z-dn.net/?f=%5B4x%5E%7B2%7D%2B16x%2B16%5D-%282x%5E%7B2%7D%20%2B6%29)
=
=
Thus, The correct option is B).
18 units squared multiply 6 times 3 to get this answer- 18u^2
Answer:
Step-by-step explanation:
At the point where Roshonda and James meet each other, they must have covered equal distances.
Let x represent the distance that Roshonda covered while riding from school to home and also the distance covered by James while travelling in a bus from school.
Let t represent the time it took Roshonda to cover x miles.
Distance = speed × time
Therefore
x = 12 × t = 12t
James left school 0.25 hours later at a speed of 35 miles per hour. Time spent by James in covering x miles would be t - 0.25.
Distance covered would be
x = 35(t - 0.25) = 35t - 8.75
Since the distance covered is the same, then,
12t = 35t - 8.75
35t - 12t = 8.75
23t = 8.75
t = 8.75/23 = 0.38 hours
0.38 + 0.25 = 0.63 hours
0.63 × 60 = 37.8 minutes
At about 3:38 pm, they would meet
