v₀ = initial velocity of the freight train while it approach a road crossing = 16 km/h = 16 (5/18) m/s = 4.44 m/s
v = final velocity of the freight train after it crosses a road crossing = 65 km/h = 65 x 5/18 m/s = 18.06 m/s
t = time to do so = 10 min = 10 x 60 sec = 600 sec
acceleration is given as
a = (v - v₀ )/t
a = (18.06 - 4.44)/(600)
a = 0.023 m/s²
a = 294
Answer:
52(9/7)^t/1.5
Step-by-step explanation:
The function N(t) a which models the number of branches t years after Aleksandra began studying her trees ;
Initial number of branches = 52
Increment every 1.5 years = 2/7
N(t) = Initial * (1 + r)^t
t expressed per year = t/1.5
Hence,
N(t) = 52(1 + 2/7)^t/1.5
N(t) = 52(9/7)^t/1.5
Answer:2.6
Step-by-step explanation:
Use your graphing calculator of you have one and if you don't you can find one online and plug in the equation and find the intersection . If you get 2.5571 round it to the nearest tenth and you should get 2.6
Answer: The domain is 
and the range is ![\boxed{[-4, 4]}](https://tex.z-dn.net/?f=%5Cboxed%7B%5B-4%2C%204%5D%7D)
.
Step-by-step explanation:
The domain is the set of x-values and the range is the set of y-values.
Answer:
coordinates of H = (1, 0)
Coordinates of G = ( - 3.6, -2) or (5.6, -2)
Step-by-step explanation:
E(5,3) and F (2,-1) are two vertices of a square EFGH and H is in the x-axis.
Let the coordinates of H is (x, 0) and G is (a, b).
The length of side EF is
So,
And
Now
Solving (1) and (2)
b = - 2 ,
