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3 years ago

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Sierra’s book has 200 pages. If she reads 20% of her, she will have read 40 pages. If Sierra has read 120 pages of her 200 pages

book by Friday, what percentage of her book will she have read ?

1 answer:

marysya [2.9K]3 years ago

5 0

Answer:

60%

Step-by-step explanation:

Multiply 40 by 3 and you get 120 so then you multiply 20% by 3 and get 60%

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Plssssss help meh with this

Naddik [55]

Answer:

<h2><em><u>ᎪꪀsωꫀᏒ</u></em></h2>

➪-263

Step-by-step explanation:

-3x²-20

-3(-9)²-20

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2 years ago

Read 2 more answers

Solve the differential. This was in the 2016 VCE Specialist Maths Paper 1 and i'm a bit stuck

Nimfa-mama [501]

$\sqrt{2 - x^{2}} \cdot \frac{dy}{dx} = \frac{1}{2 - y}$
$\frac{dy}{dx} = \frac{1}{(2 - y)\sqrt{2 - x^{2}}}$

Now, isolate the variables, so you can integrate.
$(2 - y)dy = \frac{dx}{\sqrt{2 - x^{2}}}$
$\int (2 - y)\,dy = \int\frac{dx}{\sqrt{2 - x^{2}}}$
$2y - \frac{y^{2}}{2} = sin^{-1}\frac{x}{\sqrt{2}} + \frac{1}{2}C$

$4y - y^{2} = 2sin^{-1}\frac{x}{\sqrt{2}} + C$
$y^{2} - 4y = -2sin^{-1}\frac{x}{\sqrt{2}} - C$
$(y - 2)^{2} - 4 = -2sin^{-1}\frac{x}{\sqrt{2}} - C$
$(y - 2)^{2} = 4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C$

$y - 2 = \pm\sqrt{4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C}$
$y = 2 \pm\sqrt{4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C}$

At x = 1, y = 0.
$0 = 2 \pm\sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}$
$-2 = \pm\sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}$

$4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C > 0$
$\therefore 2 = \sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}$

$4 = 4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C$
$0 = -2sin^{-1}\frac{1}{\sqrt{2}} - C$
$C = -2sin^{-1}\frac{1}{\sqrt{2}} = -2\frac{\pi}{4}$
$C = -\frac{\pi}{2}$

$\therefore y = 2 - \sqrt{4 + \frac{\pi}{2} - 2sin^{-1}\frac{x}{\sqrt{2}}}$

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3 years ago

Given A = {1, 3, 5, 7, 9}, B = {2, 4, 6, 8, 10}, C = {1, 5, 6, 7, 9}

andrey2020 [161]

Answer:

ummmm thats not even a question

Step-by-step explanation:

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2 years ago

Which recursive sequence would produce the sequence 8,-35,137,…?

vagabundo [1.1K]

The recursive sequence that would produce the sequence 8,-35,137,… is T(n + 1) = -3 - 4T(n) where T(1) = 8

<h3>How to determine the recursive sequence that would produce the sequence?</h3>

The sequence is given as:

8,-35,137,…

From the above sequence, we can see that:

The next term is the product of the current term and -4 added to -3

i.e.

Next term = -3 + Current term * -4

So, we have:

T(n + 1) = -3 + T(n) * -4

Rewrite as:

T(n + 1) = -3 - 4T(n)

Hence, the recursive sequence that would produce the sequence 8,-35,137,… is T(n + 1) = -3 - 4T(n) where T(1) = 8

Read more about recursive sequence at

brainly.com/question/1275192

#SPJ1

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1 year ago

Select the equation that contains the points (-2 -2) and (4 10)

Brums [2.3K]

Answer: y-6= 2(x-2)

Step-by-step explanation:

find the slope then put it in point slope form.

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2 years ago