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attashe74 [19]
2 years ago
12

Suppose a principal amount of $7500 was invested at an interest rate of 6%. How long did it take to reach $10650?

Mathematics
1 answer:
Oliga [24]2 years ago
6 0

Based on the information how long did it take to reach $10650 is 7years.

Given:

Principal=$7,500

Rate=6%

Amount=$10650

Time=?

Simple Interest(SI)=A-P

=$10650-$7500

=$3150

Time=(100×SI)/(p×r)

T=(100×3150)/(7500×6)

T=315,000/45,000

T=7 years

Inconclusion how long did it take to reach $10650 is 7years.

Learn more here:

brainly.com/question/15610358

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nlexa [21]

Step-by-step explanation:

To show that a statement is a tautology using truth table - is to show that all the entries in the expression are truths T.

We can do this by taking each statement, expression by expression. For example, to show that

[~p ∧ (p ∨ q)] → q

is a tautology, knowing we have 3 columns, we have 2^3 = 8 rows. We start by putting putting truth values for p, q, and r respectively

Next, we find ~p, then find (p ∨ q), then find ~p ∧ (p ∨ q), before finally arriving at the required [~p ∧ (p ∨ q)] → q

TERMINOLOGIES AND SYMBOLS

- T means Truth

- F means False

- ~p means negation of p.

~p is F if p is T, and vice versa

- ∧ means conjunction.

p ∧ q is T only if p is T and q is T.

- ∨ means disjunction.

p ∨ q is T if either p or q is T.

- → is for conditional 'if then'

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THE STEP BY STEP WORKINGS FOR THE STATEMENTS GIVEN ARE IN THE ATTACHMENT.

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Answer:

(arranged from top to bottom)

System #3, where x=6

System #1, where x=4

System #7, where x=3

System #5, where x=2

System #2, where x=1

Step-by-step explanation:

System #1: x=4

2x+y=10\\x-3y=-2

To solve, start by isolating your first equation for y.

2x+y=10\\y=-2x+10

Now, plug this value of y into your second equation.

x-3(-2x+10)=-2\\x+6x-30=-2\\7x=28\\x=4

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Isolate your second equation for y.

2x+y=4\\y=-2x+4

Plug this value of y into your first equation.

x+2(-2x+4)=5\\x+(-4x)+8=5\\x-4x+8=5\\-3x=-3\\x=1

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Isolate your first equation for y.

5x+y=33\\y=-5x+33

Plug this value of y into your second equation.

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Plug your value of y into your second equation.

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<em>all real numbers are solutions</em>

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Isolate your second equation for y.

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Plug in your value of y to your first equation.

x+3(6x-11)=5\\x+18x-33=5\\19x=38\\x=2

System #6: no solution (not included in your diagram)

2x+y=10\\-6x-3y=-2

Isolate your first equation for y.

2x+y=10\\y=-2x+10

Plug your value of y into your second equation.

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Plug your value of y into your second equation.

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the answer is c

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