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attashe74 [19]
3 years ago
12

Suppose a principal amount of $7500 was invested at an interest rate of 6%. How long did it take to reach $10650?

Mathematics
1 answer:
Oliga [24]3 years ago
6 0

Based on the information how long did it take to reach $10650 is 7years.

Given:

Principal=$7,500

Rate=6%

Amount=$10650

Time=?

Simple Interest(SI)=A-P

=$10650-$7500

=$3150

Time=(100×SI)/(p×r)

T=(100×3150)/(7500×6)

T=315,000/45,000

T=7 years

Inconclusion how long did it take to reach $10650 is 7years.

Learn more here:

brainly.com/question/15610358

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Answer:

The correct answer is -7.5 years.

Step-by-step explanation:

Given:

Principle amount = 12000

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time = ?

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We know that simple Interest I = (P*t*r)/100

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putting values in formula:

t = 4320*100/4.8*12000

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3 years ago
A scale of 0.5 inches to 2 feet was used for a model of the goal posts on a football field. If the model was 1 1/2 in high and 5
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4 years ago
Please help! if abcd is dilated by a factor of 3, the coordinate of b would be
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(-6, 6)

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The new coordinates of B' would be

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7 0
3 years ago
Read 2 more answers
Pls pls help I don’t have time HELP ASAP. It also detects if it’s right or wrong.
DaniilM [7]

Answer:

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Hope this helps ;)

8 0
3 years ago
4)
PilotLPTM [1.2K]

Answer:

|-9| = 9

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3 years ago
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