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Andrew [12]
3 years ago
14

Which container most likely contains a liquid

Physics
1 answer:
vlabodo [156]3 years ago
3 0

The container that most likely contains a liquid is container A.

Let me know if this helped or not! :)

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A cell phone company relies on which kind of waves in order to provide service for its customers?
Tanzania [10]
Radio waves are what cell phone company rely on
4 0
3 years ago
Read 2 more answers
Amy swims 500 m (0.5 km) in 6 minutes (0.1 hour ) . What was her speed in kilometers per hour ?
Scorpion4ik [409]
60 minutes = 1h
500/x = 10/100
She swam 5 kilometers per hour.
5 0
3 years ago
A battery charger is connected to a dead battery and delivers a current of 3.5 a for 4 hours, keeping the voltage across the bat
oksano4ka [1.4K]
The power delivered is equal to the product between the voltage V and the current I:
P=VI=(16 V)(3.5 A)=56 W

This power is delivered for a total time of t=4h=4 \cdot 3600 s = 14400 s, so the total energy delivered to the battery is
E=Pt = (56 W)(14400 s)=806400 J=806.4 kJ
5 0
3 years ago
A flat disk of radius 0.50 m is oriented so that the plane of the disk makes an angle of 30 degrees with a uniform electric fiel
nexus9112 [7]

Answer:

The electric flux is 280\ \rm N.m^2/C

Explanation:

Given:

  • Radius of the disc R=0.50 m
  • Angle made by disk with the horizontal \theta=30^\circ
  • Magnitude of the electric Field E=713.0\ \rm N/C

The flux of the Electric Field E due to the are dA in space can be found out by using Gauss Law which is as follows

\phi=\int E.dA

where

  • \phi is the total Electric Flux
  • E is the Electric Field
  • dA is the Area through which the electric flux is to be calculated.

Now according to question we have

=EA\cos\theta \\=713\times 3.14\times 0.5^2 \times \cos60^\circ\\=280\ \rm N.m^2/C

Hence the electric flux is calculated.

8 0
3 years ago
In certain cases, using both the momentum principle and energy principle to analyze a system is useful, as they each can reveal
kramer

Explanation:

The gravitational force equation is the following:

F_G = G * \frac{m_1 m_2}{r^2} \\

Where:

G = Gravitational constant = 6.67408 * 10^{-11} m^3 kg^{-1} s^{-2}

m1 & m2 = the mass of two related objects

r = distance between the two related objects

The problem gives you everything you need to plug into the formula, except for the gravitational constant. Let me know if you need further clarification.

8 0
3 years ago
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