How many miles long is burma from north to south?

Which law describes how the Earth applies a gravitational force on the Moon, the Moon applies a gravitational force on Earth? *

nikdorinn [45]

The answer is Newton's 3rd Law. The reason why is because a force is a push or a pull that acts upon an object as a results of its interaction with another object. ... These two forces are called action and reaction forces and are the subject ofNewton's third law of motion. Formally stated, Newton's third law is: For every action, there is an equal and opposite reaction.

3 0

3 years ago

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The siren on an ambulance is emitting a sound whose frequency is2550 Hz. The speed of sound is 343 m/s.(a) If the ambulance is s

Sati [7]

Answer:

0.13451 m

0.124196 m

0.119997901132 m

Explanation:

$v_o$ = Velocity of the observer

$v_s$ = Velocity of sound source

v = Velocity of sound in air = 343 m/s

Wavelength is given by

$\lambda=\dfrac{v}{f}\\\Rightarrow \lambda=\dfrac{343}{2550}\\\Rightarrow \lambda=0.13451\ m$

The wavelength is 0.13451 m

From Doppler effect we have the formula

$f=f'\dfrac{v}{v-v_s}\\\Rightarrow f=2550\dfrac{343}{343-26.3}\\\Rightarrow f=2761.7619198\ Hz$

$\lambda=\dfrac{343}{2761.7619198}\\\Rightarrow \lambda=0.124196\ m$

The wavelength is 0.124196 m

$f=f'\dfrac{v+v_o}{v-v_s}\\\Rightarrow f=2550\dfrac{343+12}{343-26.3}\\\Rightarrow f=2858.38332807\ Hz$

$\lambda=\dfrac{343}{2858.38332807}\\\Rightarrow \lambda=0.119997901132\ m$

The wavelength is 0.119997901132 m

8 0

3 years ago

A constant force of 53 newtons was applied to a 12-kilogram mass for 15 seconds. a.) What was the change in momentum of the mass

vazorg [7]

Explanation:

Impulse = change in momentum

FΔt = Δp

(53 N) (15 s) = Δp

Δp = 795 kg m/s

For constant mass:

Δp = m Δv

795 kg m/s = (12 kg) Δv

Δv = 66.25 m/s

Rounding to two significant figures, Δp = 800 kg m/s and Δv = 66 m/s.

8 0

3 years ago

How much voltage is required to run 0.054 A of current through a 15 resistor? Use AV=IR. O A. 2.8 x 102 v O B. 1.2 V O C. 3.6 x

olga55 [171]

Answer:the answer is D

Explanation:

Plug variables in and calculate

6 0

3 years ago

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A spring has a force constant of 500.0 N/m. Show that the potential energy stored in the spring is as follows: a. 0.400 J when t

kogti [31]

Answer:

(a) Hence, the potential energy = 0.400 J.

(b) Hence the potential Energy = 0.225 J.

(c) Hence the potential energy = 0 J

Explanation:

Potential Energy; This is the energy of a body, by virtue of its position in the gravitational field. The unit of potential energy is Joules (J)

the potential energy stored in a spring is

Ep = 1/2ke²..................................... Equation 1

Where Ep = potential Energy, k = force constant, e = extension.

a.

When spring is stretched 4.00 cm, e = 4.00 cm = 4/100 = 0.04 m, and k = 500 N/m.

Substituting into equation 1

Ep = 1/2(500)(0.04)²

Ep = 0.4 J.

Hence, the potential energy = 0.400 J.

(b)

When the spring is compressed 3.00 cm, e = 3.00 cm = 3/100 = 0.03 m, and k = 500 N/m.

Substitute into equation 1,

Ep = 1/2(500)(0.03)²

Ep = 250(0.0009)

Ep = 0.225 J.

Hence the potential Energy = 0.225 J.

(c) When the spring is unstretched, e = 0 cm = 0 m and k = 500 N/m.

Substituting into equation 1

Ep = 1/2(500)(0)²

Ep = 250(0)

Ep = 0.

Hence the potential energy = 0 J

3 0

3 years ago