Answer:
C. Pulmonary endurance
Explanation:
I'm pretty sure it's "C" because cardiovascular and pulmonary endurance are the same thing and usually you'd hear cardiovascular more than pulmonary.
Sorry if I'm wrong!
Neptune was named after the Roman god of the sea and it is the last known of the planets
To solve this problem it is necessary to apply the concepts related to the kinematic equations of movement description.
From the definition we know that the speed of a body can be described as a function of gravity and height



Then applying the kinematic equation of displacement, the height can be written as

Re-arrange to find t,



Thus the calculation of the displacement would be subject to



Therefore the required distance must be 0.547m
Answer:
Part a)

Part b)
Since the radius is decreasing so induced current will increase the flux through the coil
So it would be clockwise in direction
Explanation:
As we know that magnetic flux linked with the coil is given as

now the rate of change in flux is given as

now we know that circumference is decreasing at rate of 15 cm/s
so here we know the length of circumference as

So rate of change in circumference is


final length of circumference at t = 8 s

Part a)
Now the induced EMF is given as



Part b)
Since the radius is decreasing so induced current will increase the flux through the coil
So it would be clockwise in direction