Answer:
1. Volume as STP = 755 L
2. Outside temperature = 255 K
3. Percentage yield = 70.5%
Explanation:
1. At STP, pressure = 101.3 kpa, temperature = 0°C or 273.15 K
Using the general gas equation :
P1V1/T1 = P2V2/T2
P1 = 620 kpa
V1 = 140 L
T1 = 37°C or (273.15 + 37) K = 310.15 K
P2 = 101.3 kpa
V2 = ?
T2 = 273.15 K
V2 = P1V1T2/P2T1
V2 = 620 × 140 × 273.15 / 101.3 × 310.15
V2 = 755 L
2. Using Charles' gas law:
V1/T1 = V2/T2
V1 = 2.5 L
T1 = 290 K
V2 = 2.2 L
T2 = ?
T2 = V2T1/VI
T2 = 2.2 × 290 / 2.5
T2 = 255 K
3. Equation of reaction : 2 Al + 3 CuSO4 ---> Al2 (SO4)3 + 3 Cu
From equation of the reaction, 2 moles of Al produces 3 moles of Cu
Molar mass of Al = 27 g; Molar mass of Cu = 63.5 g
2 moles of Al = 2 × 27 g = 54 g; 3 moles of Cu = 3× 63.5 = 190.5 g
54 g of Al produces 190.5 g of Cu
1.87 g of Al will produce 190.5/54 × 1.87 g of Cu = 6.60 g of Cu
Percentage yield = actual yield /theoretical yield × 100%
Percentage yield = 4.65/6.60 × 100%
Percentage yield = 70.5%
There should be a sufficient amount of the selected isotope in the rock.
The half-life of the isotope must be long enough to capture the age of the rock.
Explanation:
Sully must consider two main aspect before selecting her choice isotope for dating.
There must be sufficient amount of the selected isotope in the rock.
The half - life of the isotope must be long enough to capture the age of the rock.
- Radiometric dating gives a rock an absolute numerical age.
- The half-life of an isotope is time take for half of a radioactive element to decay.
- If the half-life of an isotope is very short, all the parent nuclide would have turned to daughter nuclides.
- Also, we must have sufficient amount of both the daughter and parent isotope in the selected rock.
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<em>≈ 4.10 g/cm³</em>
<em>Hi there ! </em>
<em><u /></em>
<em><u>Density formula</u></em>
<em>d = m/V</em>
<em>d = 6.13g/1.5cm³</em>
<em>d = 4.08(6) g/cm³ ≈ 4.10 g/cm³</em>
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<em>Good luck !</em>
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