3 years ago

Please someone help me with this.

1 answer:

6 0

The shaded triangle at the bottom right has an area of 1/2 x base x height.
This equates to 1/2 x 2in x 4in which should equal 4in^2/

4 square inches.

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What is the length of the major axis of the conic section shown below?

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$\dfrac{(x-2)^2}{49}+\dfrac{(y+5)^2}{36}=1$

The equation of a elipse:

$\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1$

The length of the major axis is equal 2a if a > b or 2b if b > a.

We have

$a^2=49\to a=\sqrt{49}=7\\\\b^2=36\to b=\sqrt{36}=6\\\\a > b$

therefore the length of the major axis is equal 2 · 7 = 14.

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