You should must check for an extraneous solution when the variable appears both inside and outside the absolute value expression
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What is an extraneous solution?</h3>
An extraneous solution is a solution that in obtained after completely solving an equation but it does not work in the original given equation.
You should must check for an extraneous solution when the variable appears both inside and outside the absolute value expression (Option D).
Learn more about extraneous solution: brainly.com/question/14054707
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Answer:
The area of the base plate is 120 in
Step-by-step explanation:
Answer:
Solve for x: -5/6x= -10/3 x=?
x = 1/4
Step-by-step explanation:
from the equation ,Solve for x: -5/6x= -10/3 , to solve for x we will first cross multiply
we have; -15= -60x
divide both sides by -60
-15/-60 = -60x/-60
x = 15/60 ( the minus will cancel out)
x = 1/4
check for your answer by putting 1/4 where you see x
i.e -5/6(1/4) = -10/3
-5 × 2/3 = -10/3
-10/3 = -10/3......... proved!!
Answer:
9
Step-by-step explanation:
I think what they are asking is to subtract the 3 tokens from 21 tokens he already has giving us 18. and since it says "Twice the number of tokens" I'm assuming you divide 2 from 18 giving you 9 tokens.
Answer:
75
Step-by-step explanation:
75m/hr
