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prisoha [69]
4 years ago
9

Which is more concentrated with respect to sodium ions, 50.0 g of NaCl dissolved in 500.0 mL of solution or 59.0 g of Na2SO4 in

500.0 mL of solution? a They are equal in concentration b The NaCl solution described c The Na2SO4 solution described Question 12 (1 point) What percentage of sodium sulfate molecules are separated when placed in water? a 50% b 100% c 10% d 80%
Chemistry
1 answer:
Dmitry_Shevchenko [17]4 years ago
7 0

Answer:

b) The NaCl solution described

Explanation:

First we calculate the number of moles for each compound:

moles = mass / molecular weight

moles of NaCl = 50 / 58.5 = 0.854 moles

moles of Na₂SO₄ = 59 / 142 = 0.415 moles

In the first solution we have:

0.854 moles of NaCl which means that 0.854 moles of sodium Na⁺ ions are dissolved in 500 mL of solution

In the second solution we have:

0.415 moles of Na₂SO₄ which means that 0.843 moles of sodium Na⁺ ions are dissolved in 500 mL of solution

Now we may conclude that the NaCl is more concentrated than the Na₂SO₄ solution.

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Answer:

The correct answer to the following question will be "4.08 × 10⁻¹⁹ Joule".

Explanation:

Given:

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E=h\upsilon =\frac{hc}{\lambda}

On putting the estimated values, we get

⇒          =\frac{1241.5 \ ev\ nm}{486 \ nm}

⇒          =2.554 \ ev

∴ 1 ev = 1.6 × 10⁻¹⁹ J

Now,

Energy, E=2.554\times 1.6\times 10^{-19}

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4 years ago
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Answer:

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Explanation:

We are given;

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We are required to determine the oxidation number of S in the compound.

We need to know that;

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