Answer:
option d= 2
pH of gastric juice in stomach is vary from 1.5 - 3.5. So it could be 2.
Explanation:
Gastric juice present in the stomach is acidic in nature. It is composed of mainly sodium chloride, hydrochloric acid and potassium chloride. It is produce by the cells present in stomach lining. It activate the digestive enzyme and play important role in the digestion of protein . These enzymes break the chain of amino acids. Its acidic pH is not harmful for the stomach because lining cells of stomach also produce mucus that act as a barrier.
Chemical composition of gastric juice and their functions:
The gastric juice is a mixture of several chemicals including:
water:
water can not effect the stomach pH. it provide liquidity to mix the food, acids and enzymes. some enzymes also require water to perform the function.
Mucous:
It is produce in stomach. mouth and esophagus. It passes the food through gastrointestinal track in a protected way and also provide the protection to stomach from acid.
Hydrochloric Acid:
HCl is secreted by parietal cells of stomach. it kills the pathogens and bacteria in food and also convert the pepsinogen into pepsin. pepsin breaks the secondary and tertiary proteins and help in digestion.
Pepsinogen:
It also help to digest the protein.
Hormones and Electrolytes:
They help in food digestion and nutrient absorption.
Gastric Lipase:
t help to breake the fats of short and medium chain.
Amylase:
It is found in saliva and break down the carbohydrates.
a) The sizes of punch and blanking are equivalent to its diameters. The blanking die diameter is Db = 65 mm
Diameter of the blanking punch is,
dpunch = Db - 2c
Here, c = Ac (thickness)
For aluminium, Ac = 0.06
c = (0.06) (3.2 mm) = 0.192 mm
dpunch = (65 mm) - 2 (0.192 mm)
= 64.616 mm
b) The diameter of the punching punch is equivalent to the interior diameter of the washer.
Thus, diameter of the punching die is, Dh = 30 mm
Diameter of the punching die is,
ddie = Dh + 2c
= (30 mm) + 2 (0.192)
= 30.384 mm
Answer:
Mass of Ag produced = 64.6 g
Note: the question is, how many grams of Ag is produced from 19.0 g of Cu and 125 g of AgNO3
Explanation:
Equation of the reaction:
Cu + 2AgNO3 ---> 2Ag + Cu(NO3)2
From the equation above, 1 mole of Cu reacts with 2 moles of AgNO3 to produce 2 moles of Ag and 1 mole of Cu(NO3)2.
Molar mass of the reactants and products are; Cu = 63.5 g/mol, Ag = 108 g/mol, AgNO3 = 170 g/mol, Cu(NO3)2 = 187.5 g/mol
To determine, the limiting reactant;
63.5 g of Cu reacts with 170 * 2 g of AgNO3,
19 g of Cu will react with (340 * 19)/63.5 g of AgNO3 =101.7 g of AgNO3.
Since there are 125 g of AgNO3 available for reaction, it is in excess and Cu is the limiting reactant.
63.5 g of Cu reacts to produce 108 * 2 g of Ag,
19 g of Cu will react to produce (216 * 19)/63.5 g of Ag = 64.6 g of Ag.
Therefore mass of Ag produced = 64.6g
Answer:
so the number of molecules in 8 moles of water is 4.8176×10^24
Explanation:
number of moles=8moles
avogadro's number=6.022×10²³
number of molecules=?
as we know that
substituting the equation
number of moles × avogdro's number=number of molecules
number of molecules=8moles×6.022×10²³
number of molecules=4.8176×10^24
i hope this will help you :)
