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IceJOKER [234]
3 years ago
7

Explain the relationship between an individual and a Society​

Chemistry
1 answer:
Rufina [12.5K]3 years ago
6 0

Answer:

the relationship between an individual and a society is society doesn't exist independently without an individual .the individual lives and acts within society but society is nothing ,in spite of the combination of individual s for cooperation effort.

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Can the structure of an atom be broken down into smaller parts?
mel-nik [20]

Answer

yes it can because it can be split in to neutrons and electrons.

Explanation:

6 0
3 years ago
Which of these is an extensive property?
Liono4ka [1.6K]

Answer:volume

i think

Explanation:

7 0
3 years ago
Which of these elements has the highest first ionization energy?
julia-pushkina [17]

Answer:

Cesium (Cs)

Explanation:

This eliment has an ionization energy of 3,8939

6 0
3 years ago
rite an equation for the formation one mole of CaCO3(s) from its elements in their standard states. Write any reference to carbo
maks197457 [2]

Answer: The chemical equation for the formation one mole of CaCO3(s) from its elements in their standard states is Ca(s)+C(s)+\frac{3}{2}O_2(g)\rightarrow CaCO_3(s)

Explanation:

The standard enthalpy of formation or standard heat of formation of a compound is the change of enthalpy during the formation of 1 mole of the substance from its constituent elements, with all substances in their standard states.

The chemical equation for the formation one mole of CaCO3(s) from its elements in their standard states is:

Ca(s)+C(s)+\frac{3}{2}O_2(g)\rightarrow CaCO_3(s)

where (s) represents solid state and (g) represents gaseous state.

6 0
3 years ago
Given a fixed amount of gas in a rigid container (no change in volume), what pressure will the gas exert if the pressure is init
Masja [62]

Answer:

The pressure the gas will have if the pressure is initially 1.50 atm at 22.0 ° C and the temperature changes at 11.0 ° C is 1.44 atm (option D)

Explanation:

Gay Lussac's law indicates that, as long as the volume of the container containing the gas is constant, as the temperature increases, the gas molecules move more rapidly. Then the number of collisions against the walls increases, that is, the pressure increases. That is, the gas pressure is directly proportional to its temperature.

Gay-Lussac's law can be expressed mathematically as follows:

\frac{P}{T}=k

Where P = pressure, T = temperature, K = Constant

You have a gas that is at a pressure P1 and at a temperature T1. When the temperature varies to a new T2 value, then the pressure will change to P2, and then:

\frac{P1}{T1}=\frac{P2}{T2}

In this case:

  • P1= 1.50 atm
  • T1= 22 °C= 295 °K (being 0°C= 273 °K)
  • P2= ?
  • T2= 11 °C= 284 K

Replacing:

\frac{1.5 atm}{295 K}=\frac{P2}{284 K}

Solving:

P2= 284 K*\frac{1.5 atm}{295 K}

P2=1.44 atm

<u><em>The pressure the gas will have if the pressure is initially 1.50 atm at 22.0 ° C and the temperature changes at 11.0 ° C is 1.44 atm (option D)</em></u>

8 0
3 years ago
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