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2 years ago

If ∠1 and ∠2 are complementary and m∠1= 17°, what is m∠2?

Mathematics

1 answer:

hichkok12 [17]2 years ago

5 0

Complementary angles add up to 90*. Therefore, the logical answer would be
D, 77.

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Makovka662 [10]

Let $u=x^2-4$ and $v=4x-5$ . By the product rule,

$\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=\dfrac{\mathrm d(u^5)}{\mathrm dx}v^4+u^5\dfrac{\mathrm d(v^4)}{\mathrm dx}$

By the power rule, we have $(u^5)'=5u^4$ and $(v^4)'=4v^3$ , but $u,v$ are functions of $x$ , so we also need to apply the chain rule:

$\dfrac{\mathrm d(u^5)}{\mathrm dx}=5u^4\dfrac{\mathrm du}{\mathrm dx}$

$\dfrac{\mathrm d(v^4)}{\mathrm dx}=4v^3\dfrac{\mathrm dv}{\mathrm dx}$

and we have

$\dfrac{\mathrm du}{\mathrm dx}=2x$

$\dfrac{\mathrm dv}{\mathrm dx}=4$

So we end up with

$\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=10xu^4v^4+16u^5v^3$

Replace $u,v$ to get everything in terms of $x$ :

$\dfrac{\mathrm d((x^2-4)^5(4x-5)^4)}{\mathrm dx}=10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3$

We can simplify this by factoring:

$10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3=2(x^2-4)^4(4x-5)^3\bigg(5x(4x-5)+8(x^2-4)\bigg)$

$=2(x^2-4)^4(4x-5)^3(28x^2-57)$

7 0

2 years ago

What is the correct solution to (x+2)(x+5)

elena-s [515]

Answer:

x^2+7x+10

Step-by-step explanation:

multiply the first by first and first by second

multiply the second by first and second by second

7 0

2 years ago

Use the greatest common factor to write the fraction in simplest form: 32/48

Illusion [34]

Answer:

Divide both by 8

Which gives you

4/6

That can be simplest form by 2

2/3 is your final answer!

8 0

2 years ago

If y = -6cosx, what is the amplitude?

aniked [119]

$\displaystyle\bf\\y=-6cos\,x\\\\\textbf{is equivalent to:}\\\\y=6cos(x+\pi)\\\\\textbf{where 6 is the maximum value or amplitude}\\\\\implies~~~\boxed{\bf~amplitude=6}$

8 0

2 years ago

Does the table represent a linear or an exponential function? Explain.

leva [86]

we can use MS excel to plot the given data and check whether the graph's trendline has an R-squared of 1. The graph does not fit into a line but fits into an exponential function. The trendline's equation is equal to y = 4e^1.3863x where R squared is equal to 1

6 0

2 years ago