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MissTica
3 years ago
15

NEED HELP PLEASE!!!!!!!

Mathematics
1 answer:
lozanna [386]3 years ago
3 0
If the sales representative is able to get 20% of the prospective customers to subscribe, the maximum expected number of subscriptions per week is 34. If the sales representative earns $3 per subscription in addition to daily wages, the minimum expected value of the extra income per week is $94.20.

For the first answer, refer to the attached solution. Add the data each week, then multiply the sum by 20% to find out which has the maximum expected number of subscriptions.

For the second answer, the minimum expected value in week 2 multiplied by $3 to get the minimum expected value of the extra income in that week.

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Draw a bar model that shows a pen is 4 times as long as an araser is 1 1/3
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Apply and extend previous understandings of multiplication to multiply a fraction by a whole number. Solve word problems involving multiplication of a fraction by a whole number, e.g., by using visual fraction models. 
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4 years ago
M3 - 8m + 2 cuando m = -5​
Novay_Z [31]

Answer:

<h2>-5*3 -8*-5 +2</h2><h2>= -15 +40 +2</h2><h2>= 27</h2>
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3 years ago
What is the product of (4x + 3)(-2x - 5)?
Yuki888 [10]

Answer:

A) -8x^2 - 26x - 15

Step-by-step explanation:

(4x + 3)(-2x - 5)

FOIL

first:  4x*-2x = -8x^2

outer : -5*4x = -20x

inner: -2x*3 = -6x

last: -5*3 = -15

Add these together

-8x^2 -20x-6x -15

-8x^2 -26x-15


5 0
3 years ago
the intensity, I, of light varies inversely as the square of the distance, D2 , from the light source. If I is 150 units when D
podryga [215]

\bf \textit{\underline{x} varies inversely with }\underline{z^5} ~\hspace{5.5em} \stackrel{\textit{constant of variation}}{x=\cfrac{\stackrel{\downarrow }{k}}{z^5}~\hfill } \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{\textit{\underline{I} varies inversely with }\underline{D^2}}{I = \cfrac{k}{D^2}} \qquad \qquad \textit{we also know that } \begin{cases} I=150\\ D=6 \end{cases}

\bf 150=\cfrac{k}{6^2}\implies 150=\cfrac{k}{36}\implies 5400=k~\hfill \boxed{I=\cfrac{5400}{D^2}} \\\\\\ \textit{when I = 24, what is \underline{D}?}\qquad \qquad 24=\cfrac{5400}{D^2}\implies D^2=\cfrac{5400}{24} \\\\\\ D^2=225\implies D=\sqrt{225}\implies D=15

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4 years ago
5) Which one of the following proportions is NOT true?*
Tpy6a [65]
The second one, 69/24 = 23/8 and cannot be simplified further
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4 years ago
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