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Step2247 [10]
3 years ago
10

Determine the complement and/or supplement of each angle

Mathematics
1 answer:
Wewaii [24]3 years ago
7 0

And/or?

Complementary angles add to 90 degrees.  Supplementary angles add to 180 degrees.

a. 15°

Complement: 90 - 15 = 75°          Supplement: 180 - 15 = 165°

b. 37°

These are boring.

Complement: 90 - 37 = 53°          Supplement: 180 - 37 = 143°

c. 71°

Complement: 90 - 71 = 19 °          Supplement: 180 - 71 = 109°

d. 63°

Complement: 90 - 63 = 27°          Supplement: 180 - 63 = 117°

e. x°

Complement: (90 - x)°          Supplement: (180 - x)°


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The graph below represents the solution set of which inequality?
natulia [17]

Answer:

option: B (x^2+2x-8) is correct.

Step-by-step explanation:

We are given the solution set as seen from the graph as:

(-4,2)

1)

On solving the first inequality we have:

x^2-2x-8

On using the method of splitting the middle term we have:

x^2-4x+2x-8

⇒  x(x-4)+2(x-4)=0

⇒ (x+2)(x-4)

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

x+2>0 and x-4

i.e. x>-2 and x<4

so we have the region as:

(-2,4)

Case 2:

x+2 and x-4>0

i.e. x<-2 and x>4

Hence, we did not get a common region.

Hence from both the cases we did not get the required region.

Hence, option 1 is incorrect.

2)

We are given the second inequality as:

x^2+2x-8

On using the method of splitting the middle term we have:

x^2+4x-2x-8

⇒ x(x+4)-2(x+4)

⇒ (x-2)(x+4)

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

x-2>0 and x+4

i.e. x>2 and x<-4

Hence, we do not get a common region.

Case 2:

x-2 and x+4>0

i.e. x<2 and x>-4

Hence the common region is (-4,2) which is same as the given option.

Hence, option B is correct.

3)

x^2-2x-8>0

On using the method of splitting the middle term we have:

x^2-4x+2x-8>0

⇒ x(x-4)+2(x-4)>0

⇒ (x-4)(x+2)>0

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

x+2>0 and x-4>0

i.e. x>-2 and x>4

Hence, the common region is (4,∞)

Case 2:

x+2 and x-4

i.e. x<-2 and x<4

Hence, the common region is: (-∞,-2)

Hence, from both the cases we did not get the desired answer.

Hence, option C is incorrect.

4)

x^2+2x-8>0

On using the method of splitting the middle term we have:

x^2+4x-2x-8>0

⇒ x(x+4)-2(x+4)>0

⇒ (x-2)(X+4)>0

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

x-2 and x+4

i.e. x<2 and x<-4

Hence, the common region is: (-∞,-4)

Case 2:

x-2>0 and x+4>0

i.e. x>2 and x>-4.

Hence, the common region is: (2,∞)

Hence from both the case we do not have the desired region.

Hence, option D is incorrect.




5 0
3 years ago
How many times can 56 go into 984
dybincka [34]

17 times evenly, all you have to do is divide 984 by 56 to get your answer.

5 0
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Read 2 more answers
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nata0808 [166]

Answer:

3^4 = 81

Step-by-step explanation:

3x3x3x3

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4 0
3 years ago
Read 2 more answers
0.65 repeating as a decimal
vladimir1956 [14]
If .65 were to repeat it would be .656565656565656


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3 years ago
Carl has three lengths of cable,
elena-s [515]
Lowest common denominator for 3,4,6 is 12

5/6 = 10/12
1/4 = 3/12
2/3 = 8/12

a)
10/12 + 3/12 = 13/12 = 1 1/12
So you need to use first and second cables

b)
3/12 + 8/12 = 11/12
To reach 1 yard Carl need 1/12 yard cable
6 0
3 years ago
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