Answer:
Mass of chlorine = 47.22 g
Explanation:
Given data:
Mass of sodium = 30.5 g
Mass of chlorine= ?
Solution:
Chemical equation:
2Na + Cl₂ → 2NaCl
Number of moles of Na:
Number of moles = mass/molar mass
Number of moles = 30.5g/ 23 g/mol
Number of moles = 1.33 mol
Now we will compare the moles of Cl
₂ with Na from balance chemical equation.
Na : Cl
₂
2 : 1
1.33 : 1/2×1.33 = 0.665 mol
Mass of chlorine gas:
Mass = number of moles × molar mass
Mass = 0.665 mol × 71 g/mol
Mass = 47.22 g
They eat autotrophs, or each other. That's how they get energy.
Hope that answered your question.
Answer: Medicine is a scientific field whose subject of research is the health and well-being of living whips.
Explanation:
Primarily medicine deals with the study of man and the treatment of man, but also of some animal species. Two principles are founded: theoretical research and practical, or often called a clinical policy. The academic and research law will enable a specific area, disease, congenital disability, or condition to be defined, studied in detail, and after the conclusion of tests performed. Concluded medical theory is most often put into a usable form through various educational processes, which will lead to the ultimate goal - to improve the health of living forms on which this theory will be applied.
Answer:
The reaction that occurs is a redox reaction. The Copper metal (Cu 0)on the copper pennies is oxidized in concentrated nitric acid to produce Cu2+ ions. Copper is easily oxidized to Cu2+, which is blue in aqueous solutions (water) so you should see the solution turn blue as the copper penny reacts.
Have a nice day ;)(^-^)
Answer:
CH3COOH will be the acid, because it is the stronger acid.
Explanation:
When an acid deprotonates in a solution, an equilibrium reaction will occur between the protonated form and the deprotonated form (conjugate base) of it. The equilibrium is characterized by the value of Ka, the equilibrium constant, which is the multiplication of the concentration of the products divided by the concentration of the acid.
As higher is the value of Ka, more acid is deprotonated, and stronger will be the acid. The value of pKa = -logKa, and so, as higher is the Ka, as low is the pKa. Thus, strong acids have low pKa values.
In the reaction of CH3COOH and H2O, the first one has a low value of pKa, so it is a strong acid. The water is a substance that can work as an acid or as a base, and, because of the other substance is a strong acid, it works as a base.
