Before it is released it as potential energy and after it has been released it transforms into kinetic energy.
I think the mineral characteristics that the one gram sample of hematite taking up more space than a one gram sample of malachite is DENSITY.
The density of hematite is 5.26 g/cm³
The density of malachite is 3.6 to 4 g/cm³
Other physical characteristics of minerals are <span><span>Color, </span>Streak, Luster, H<span>ardness, </span>Cleavage, Fracture, Tenacity, and Crystal <span>Habit.</span></span>
<span>Raising
the temperature of the reactants increases the reaction between the reactants.
The kinetic energy of the molecules of the reactants collides more frequently
with ach other thereby increasing its reaction. Increasing the concentration of
the reactants increases the reaction rate. Adding a catalyst to the reaction
increases the rate of reaction of a substance. The catalyst hastens the
chemical reaction. </span>
<u>Answer:</u>
The percent composition of this compound is 94%
<u>Explanation:</u>
The reaction can be formed as






Based on no. of iron reacted,

n = m/M

% composition of
= 
= 94%