Answer:
57.6g
Explanation:
So, if in one mole of water, 16 g of oxygen atom is present. Then, in 3.6 moles of water, the mass of oxygen present will be 3.6×16=57.6g. Therefore, the amount of oxygen present in 3.6 g water is option (B)- 57.6 g.
The correct order given below shows the changes that occurs in a mice population in response to changes in their environment:
- The population of mice is in an environment with many black rocks
- Mice with black for are more likely to survive and reproduce than mice with brown fur
- After many generations, most of the mice in the population have black fur
- A sandstorm covers most of the population's environment with brown sand
- Mice with black fur are less likely to survive and reproduce than mice with brown fur
- After many generations, most of the mice in the population have brown fur
<h3>What is the correct order for natural selection in the desert environment given?</h3>
Based on the process of natural selection due to envrionmental pressures, the population of the mice in the desert changes as follows before and after the environmental change:
- The population of mice is in an environment with many black rocks
- Mice with black for are more likely to survive and reproduce than mice with brown fur
- After many generations, most of the mice in the population have black fur
- A sandstorm covers most of the population's environment with brown sand
- Mice with black fur are less likely to survive and reproduce than mice with brown fur
- After many generations, most of the mice in the population have brown fur
Therefore, the correct order shows the changes that occurs in a mice population in response to changes in their environment.
Learn more about about adaptation at: brainly.com/question/25594630
A second order reaction varies with the square of the concentration of the reactant. Therefore, halving the concentration will reduce the rate of reaction by a factor of 4.
The answer is E.
<u>Answer:</u> The rate law of the reaction is ![\text{Rate}=k[HgCl_2][C_2O_4^{2-}]^2](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%5BHgCl_2%5D%5BC_2O_4%5E%7B2-%7D%5D%5E2)
<u>Explanation:</u>
Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.
For the given chemical equation:
Rate law expression for the reaction:
![\text{Rate}=k[HgCl_2]^a[C_2O_4^{2-}]^b](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%5BHgCl_2%5D%5Ea%5BC_2O_4%5E%7B2-%7D%5D%5Eb)
where,
a = order with respect to 
b = order with respect to 
Expression for rate law for first observation:
....(1)
Expression for rate law for second observation:
....(2)
Expression for rate law for third observation:
....(3)
Expression for rate law for fourth observation:
....(4)
Dividing 2 from 1, we get:
Dividing 2 from 3, we get:
Thus, the rate law becomes:
![\text{Rate}=k[HgCl_2]^1[C_2O_4^{2-}]^2](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%5BHgCl_2%5D%5E1%5BC_2O_4%5E%7B2-%7D%5D%5E2)
