8255 min = _?_days I need help please
1 answer:
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Explanation:
C: ΔH=+178 kJ/mol
For an endothermic reaction, heat is getting absorbed during a chemical reaction and is written on the reactant side.
Any change in the equilibrium is studied on the basis of Le-Chatelier's principle. This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.
Treat heat as a reactant and on increasing a reactant at equilibrium, shifts the reaction in the forward direction.
Increase temperature → increase in heat → forward direction
Decrease temperature → decease in heat → backward direction
System C - Increase temperature : Reaction will move forward
System C - Decrease temperature : Reaction will move backward
D: ΔH=−88 kJ/mol
The total enthalpy of the reaction comes out to be negative .
The temperature of the surrounding will increase.
For an exothermic reaction, heat is released during a chemical reaction and is written on the product side.
Any change in the equilibrium is studied on the basis of Le-Chatelier's principle. This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.
Treat heat as a product and on increasing a product at equilibrium, shifts the reaction in the backward direction.
Increase temperature → increase in heat → backward direction
Decrease temperature → decease in heat → forward direction
System D - Increase temperature : Reaction will move backward
System D - Decrease temperature : Reaction will move forward
Answer : The rate of effusion of sulfur dioxide gas is 52 mL/s.
Solution :
According to the Graham's law, the rate of effusion of gas is inversely proportional to the square root of the molar mass of gas.
or,
..........(1)
where,
= rate of effusion of nitrogen gas =
= rate of effusion of sulfur dioxide gas = ?
= molar mass of nitrogen gas = 28 g/mole
= molar mass of sulfur dioxide gas = 64 g/mole
Now put all the given values in the above formula 1, we get:
Therefore, the rate of effusion of sulfur dioxide gas is 52 mL/s.