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3 years ago

If you want to test whether a rock has calcite in it you could use the ?

1 answer:

6 0

You could use the "Vinegar Test." Students can use vinegar instead of hydrochloric acid for an introduction to the acid test which tests calcite.

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How many valence electrons does this atom have ? 1s^2 2s^2 2p^6 3s^2

tangare [24]

Answer

there is 2 electrons on that atoms

Explanation:

5 0

3 years ago

What solutes are soluble in water?

marusya05 [52]

Answer:

Ionic compounds, such as sodium chloride, are also highly soluble in water. Because water molecules are polar, they interact with the sodium and chloride ions. In general, polar solvents dissolve polar solutes, and nonpolar solvents dissolve nonpolar solutes.

Explanation:

5 0

4 years ago

(b) in the direct hydration method, ethene reacts with steam. The equation for this reaction is C2H4 + H2O = C2H5OH

ladessa [460]

Answer:

20 degree and 4000000N

3 0

3 years ago

If 30.0 g absorbs 255 J of heat, how much does the temperature of the water change? Would the temperature be increasing or decre

Nutka1998 [239]

<h3>Answer:</h3>

Change in temperature = 2.03°C, the temperature is increasing

<h3>Explanation:</h3>

To calculate the quantity of heat absorbed or released by a substance we multiply mass of the substance by it's specific heat capacity and the temperature change.
Therefore, Quantity of heat, Q = mass × specific heat × change in temperature

In this case;

Mass of water = 30.0 g

Quantity of heat absorbed = 255 J

Specific heat capacity of water = 4.186 J/g°C

Rearranging the formula, Δt = Q ÷ mc

Δt = 255 J ÷ (4.186 J/g°C×30.0 g )

= 2.03 °C

The temperature change is 2.03°C, the temperature is therefore increasing.

3 0

3 years ago

A student working in the laboratory produces 6.81 grams of calcium oxide, CaO, from 20.7 grams of calcium

xz_007 [3.2K]

Answer:

A. Theoretical yield of CaO is 11.59 g

B. Percentage yield of CaO = 58.76%

Explanation:

The following data were obtained from the question:

Mass of CaCO₃ = 20.7 g

Actual yield of CaO = 6.81 g

Theoretical yield of CaO =?

Percentage yield of CaO =?

The equation for the reaction is given below:

CaCO₃ —> CaO + CO₂

Next, we shall determine the mass of CaCO₃ that decomposed and the mass of CaO produced from the balanced equation. This can be obtained as follow:

Molar mass of CaCO₃ = 40 + 12 + (3×16)

= 40 + 12 + 48

= 100 g/mol

Mass of CaCO₃ from the balanced equation = 1 × 100 = 100 g

Molar mass of CaO = 40 + 16 = 56 g/mol

Mass of CaO from the balanced equation = 1 × 56 = 56 g

SUMMARY:

From the balanced equation above,

100 g of CaCO₃ decomposed to produce 56 g of CaO.

A. Determination of the theoretical yield of CaO.

From the balanced equation above,

100 g of CaCO₃ decomposed to produce 56 g of CaO.

Therefore, 20.7 g of CaCO₃ will decompose to produce =

(20.7 × 56)/100 = 11.59 g of CaO.

Thus, the theoretical yield of CaO is 11.59 g

B. Determination of the percentage yield.

Actual yield of CaO = 6.81 g

Theoretical yield of CaO = 11.59 g

Percentage yield of CaO =?

Percentage yield = Actual yield /Theoretical yield × 100

Percentage yield = 6.81/11.59 × 100

Percentage yield of CaO = 58.76%

4 0

3 years ago