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2 years ago

Why is physical exercise often suggested if you experience an abundance of stress?

Chemistry

1 answer:

scoray [572]2 years ago

4 0

Answer:

good question

Explanation:

probably because people like to say they know things and help people with "there stress" and think that there helping them but in reality there making it where they have more :)

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Why are fibers birefringent

horrorfan [7]

Inevitable manufacturing imperfections in optical fiber leads to birefringence, which is one cause of pulse broadening in fiber-optic communications. Such imperfections can be geometrical (lack of circular symmetry), due to stress applied to the optical fiber and/or due to bending of the fiber.

4 0

2 years ago

Read 2 more answers

Elimination of the pharmaceutical IV antibiotic gentamicin follows first-order kinetics. If the half-life of gentamicin is 1.5 h

Genrish500 [490]

Explanation:

The given data is:

The half-life of gentamicin is 1.5 hrs.

The reaction follows first-order kinetics.

The initial concentration of the reactants is 8.4 x 10-5 M.

The concentration of reactant after 8 hrs can be calculated as shown below:

The formula of the half-life of the first-order reaction is:

$k=\frac{0.693}{t_1_/_2}$

Where k = rate constant

t1/2=half-life

So, the rate constant k value is:

$k=\frac{0.693}{1.5 hrs}$

The expression for the rate constant is :

$k=\frac{2.303}{t} log \frac{initial concentration}{concentration after time "t"}$

Substitute the given values and the k value in this formula to get the concentration of the reactant after time 8 hrs is shown below:

$\frac{0.693}{1.5 hrs} =\frac{2.303}{8 hrs} x log \frac{8.4x10^-^5}{y} \\ log \frac{8.4x10^-^5}{y} =1.604\\\frac{8.4x10^-^5}{y}=10^1^.^6^0^4\\\frac{8.4x10^-^5}{y}=40.18\\y=\frac{8.4x10^-^5}{40.18} \\=>y=2.09x10^-^6$

Answer: The concentration of reactant remains after 8 hours is 2.09x10^-6M.

5 0

2 years ago

What is the correct orbital diagram for carbon

Viefleur [7K]

This is a basic orbital diagram for carbon

5 0

2 years ago

Which gas below has the largest number of moles at STP?

ArbitrLikvidat [17]

Answer:

a.) 22.4 L Ne.

Explanation:

It is known that every 1.0 mol of any gas occupies 22.4 L.

For the options:

22.4 L Ne:

It represents 1.0 mol of Ne.

20 L Ar:

using cross multiplication:

1.0 mol occupies → 22.4 L.

??? mol occupies → 20 L.

The no. of moles of (20 L) Ar = (1.0 mol)(20 L)/(22.4 L) = 0.8929 mol.

2.24 L Xe:

using cross multiplication:

1.0 mol occupies → 22.4 L.

??? mol occupies → 2.24 L.

The no. of moles of (2.24 L) Xe = (1.0 mol)(2.24 L)/(22.4 L) = 0.1 mol.

So, the gas that has the largest number of moles at STP is: a.) 22.4 L Ne.

6 0

3 years ago

Consider the following elementary reaction:

Fudgin [204]

Explanation:

The equation is given as;

N2O(g) ⇄ N2(g) + O(g)

k₁ = Forward reaction

k₋₁ = Reverse Reaction

Equilibrium concentration (K) = k₁ / k₋₁

$K = \frac{[N2O] }{[N2] [ O]}$

5 0

2 years ago