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➪Methane (CH4) is oxidized with molecu- lar oxygen (O2) to carbon dioxide (CO2).
Answer: 6.64 moles of carbon.
Explanation:
Given data:
Number of moles of C = ?
Number of moles of CCl₂F₂ = 6.64 mol
Solution:
In one mole of CCl₂F₂ there is one mole of carbon two moles of chlorine and two moles of fluorine are present.
In 6.6 moles of CCl₂F₂ :
Moles of carbon = 6.64 × 1 = 6.64 moles of carbon.
Moles of chlorine = 6.64× 2 = 13.28 moles of chlorine
Moles of fluorine = 6.64× 2 = 13.28 moles of fluorine
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Answer:
about 30g
Explanation:
Molarity = mol/L
*convert mL to L*
3M=xmol/.25
xmol = .75
*convert to g
.75 mol NaOH * 40g/mol = 30 g
