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2 years ago

Find the percent decrease. Round to the nearest hundredth.: From 248 workers to 200 workers

2 answers:

5 0

Well, clearly from 248 to 200, it decreased by 48 workers.

if we take 248 to be the 100%, what is 48 off of it in percentage then?

$\bf \begin{array}{ccll}
amount&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
248&100\\
48&p
\end{array}\implies \cfrac{248}{48}=\cfrac{100}{p}\implies p=\cfrac{48\cdot 100}{248}$

Mrac [35]2 years ago

3 0

The percentile decrease is 81%. 200 is 81% of 248 :3

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A call center data set shows that in a sample of 30 individuals, 11 had prior call center experience. If we assume that the pro

ira [324]

Answer:

P(X > 5) = 0.1164 to 4 d.p.

The parameters are defined in the explanation.

Step-by-step explanation:

This is a binomial distribution problem

Binomial distribution function is represented by

P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ

n = total number of sample spaces = number of potential hires = 10

x = Number of successes required = number of potential hires that have prior call centre experience = more than half; that is, x > 5

p = probability of success = probability that any potential hire will have experience = (11/30) = 0.367

q = probability of failure = probability that any potential hire will NOT have experience = 1 - p = 1 - 0.367 = 0.633

P(X > 5) = P(X=6) + P(X=7) + P(X=8) + P(X=9) + P(X=10)

Inserting the parameters and computing the probabilities for each of those values of X,

P(X > 5) = 0.11641775484 = 0.1164 to 4 d.p.

Hope this Helps!!!

4 0

2 years ago

∠ACE is formed by two secants intersecting outside of a circle. If minor arc BD = 25°, minor arc AB = 115°, and minor arc DE = 1

dmitriy555 [2]

Answer:

m∠ACE = 40°

Step-by-step explanation:

Consider the below figure attached with this question.

Given information: arc BD = 25°, minor arc AB = 115°, and minor arc DE = 115°.

We need to find the measure of ∠ACE.

minor arc AB + minor arc BD + minor arc DE + minor arc AE = 360°

115° + 25° + 115° + minor arc AE = 360°

255° + minor arc AE = 360°

minor arc AE = 360° - 255°

minor arc AE = 105°

The measure of minor arc AE is 105°.

Using Intersecting secants outside the circle theorem

Angle between two secants = $\frac{1}{2}$ (Major arc - Minor arc)

$\angle ACE=\frac{1}{2}[Arc(AE)-Arc(BD)]$

$\angle ACE=\frac{1}{2}[105-25]$

$\angle ACE=\frac{1}{2}[80]$

$\angle ACE=40$

Therefore, the measure of ∠ACE is 40°.

3 0

2 years ago

Please help I will mark branliest

oee [108]

Answer:

$B.2w+2l$

Step-by-step explanation:

$As\ we\ are\ given\ that,\\Perimeter\ of\ any\ rectangle=w+l+w+l\\By\ adding\ the\ like\ terms\ together\ in\ the\ expression\ w+l+w+l,\\we\ get:\\(w+w)+(l+l)\\=2w+2l$